I am using webview in my application to show canvas. On my webview there is click here button. I want to open new activity on click of this 'click here' button on webview. I dont know how to handle this click event.Need help as soon as possible.
Following is my webview class code:
public class TableWebView extends Activity {
private SharedPreferences sharedPreferences;
private String customer_id,hotel_id;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_table_web_view);
WebView wvtable= (WebView)findViewById(R.id.webViewTable);
wvtable.setWebViewClient(new MyViewClient());
WebSettings webSettings = wvtable.getSettings();
webSettings.setJavaScriptEnabled(true);
sharedPreferences = PreferenceManager.getDefaultSharedPreferences(getApplicationContext());
customer_id = sharedPreferences.getString("cust_id", "0");//if no customerid found automatically 0 will be used
hotel_id=sharedPreferences.getString("hotel_master_id","0");
wvtable.loadUrl("http://192.168.100.169/zoilo_admin/public/index.php/show-hotel-view?hotel_id="+hotel_id+"&customer_id="+customer_id+"&date_time="+ Util.selected_date_time);
}
And here is how it looks after opening that url in webview: