Assignment from incompatible pointer type in (c)

Question

Here is my struct,

typedef struct radixNode *radixPtr;
struct radixNode{
 int permission;
 int end;
 fileType type;
 radixPtr link[ASCII_SIZE];
};

I'm allocating memory for radixPtr,

radixPtr q;
q= createRadixNode();

And when I try to do this

q->link[index] = createRadixNode;

gcc gives warning: assignment from incompatible pointer type in c

Here is the allocate memory function

radixPtr createRadixNode () {
 radixPtr radix_node = (radixPtr)malloc(sizeof(struct radixNode));
 int i;

 if(radix_node == NULL) {
   perror("There is no memory to create radix node");
   exit(1);
 }

 radix_node->end = -1;
 for (i = 0; i < ASCII_SIZE; ++i) {
     radix_node->link[i] = NULL;
 }
 return radix_node;
}

I can't find a way to solve this. All things looks good. Thanks for any advice.

Did you mean `q->link[index] = createRadixNode();` instead of `q->link[index] = createRadixNode;`? And don't cast the result of `malloc` and family — Spikatrix, Apr 04 '15 at 11:53
`q->link[index] = createRadixNode;` -->> `q->link[index] = createRadixNode();` — wildplasser, Apr 04 '15 at 11:53
why doesn't gcc give error like createRadixNode doesn't declared ? — Abraam, Apr 04 '15 at 11:56
@Abraam , I think that it is because the name of a function "decays" to a pointer that points to the function's address. So, `createRadixNode` is equal to `&createRadixNode`. The address of the function is used in several places like when using function pointers and multithreading(third argument of `pthread_create`) etc — Spikatrix, Apr 04 '15 at 11:57

score 0 · Accepted Answer · edited May 23 '17 at 11:50

0

What you actually want is

q->link[index] = createRadixNode();

instead of

q->link[index] = createRadixNode;

This will fix this issue. BTW, don't cast the result of malloc(and family) in C.

edited May 23 '17 at 11:50

Community

1
1

answered Apr 04 '15 at 11:56

Spikatrix

20,225
7
37
83

Assignment from incompatible pointer type in (c)

1 Answers1