i have a variable like this:
set file=c:\dir\foo\bar\file.txt
how can i get just the path-part into another variable?
echo %pathpart%
should give c:\dir\foo\bar\
thanks!
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possible duplicate of [How do I get the equivalent of dirname() in a batch file?](http://stackoverflow.com/questions/778135/how-do-i-get-the-equivalent-of-dirname-in-a-batch-file) – Matthew Whited Jun 01 '10 at 16:07
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Since some people coming here are wanting to get the filename part and not the directory, to save you time: use %~np to get only the filename and extension. For example, %~nx1 returns the value of %1 but without the drive letter or path (useful for drag-and-drop batch files). Without the extension is `~n`. – Aaron D May 15 '15 at 04:16
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1This answer provides a list of batch-script variable modifiers: http://stackoverflow.com/a/3215539/1960180 – Aaron D May 15 '15 at 04:17
