running python code despite KeyError

Question

I get a KeyError for one of the entries in the dataframe, but I would like the code to continue with the other entries which seem to have not problem. I have been reading about the except() option but don't know how to use it. Can you help

You have to show your code that raise the `KeyError` – EdChum Apr 08 '15 at 14:46 — EdChum, Apr 08 '15 at 14:46

mhawke · Answer 1 · 2015-04-08T14:58:39.883

Assuming a dataframe df, this is how you handle the KeyError exception:

import pandas
df = pandas.DataFrame()

try:
    print df[0]
except KeyError as exc:
    print "Caught KeyError: {}".format(exc)

Output

Caught KeyError: 0

The same also works on dictionaries. You can see here that the exception is bound to exc in the except clause and can be accessed within the exception handler. In Python 3, exc is not accessible outside of the except clause; in Python 2 it is accessible (but you should follow the Python 3 way).

score 2 · Accepted Answer · edited May 23 '17 at 10:24

2

The basic form of exception handling in python uses try:

try:
    #code which gives key error (replace pass with your code)
    pass

except KeyError:
    #do some exception handling here (or just pass)
    pass

edited May 23 '17 at 10:24

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answered Apr 08 '15 at 14:51

Ed Smith

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Thanks, this is just the fix I was looking for. I put the section of code that was giving the KeyError under try and passed if there was an exception – Ssank Apr 08 '15 at 15:02

running python code despite KeyError

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