PHP: echo only the last part of a url, intead code printing the whole url

Question

I wanted to print the last characters after "/" in a url. but instead it is printing the whole url, I expected the output to be just "index.php" instead it is printing out the whole url.

How should i go about doing it right?

 $data = $_SERVER['REQUEST_URI'];
    $whatIWant = substr($data, strpos($data, "/") + 1); 
     echo $whatIWant;

You can see it here

All this use of explode to hack through to the filename when PHP provides built-in functions to do it for you: `echo pathinfo(parse_url($_SERVER['REQUEST_URI'], PHP_URL_PATH), PATHINFO_BASENAME);` — Mark Baker, Apr 10 '15 at 09:27
What is the difference to this question: http://stackoverflow.com/q/29552114/3933332 ? Seems pretty similar? — Rizier123, Apr 10 '15 at 09:27
Please try strrpos.it's best solution.see the code i have given. — Alive to die - Anant, Apr 10 '15 at 09:36

score 1 · Answer 1 · answered Apr 10 '15 at 09:23

1

You should get the actual link by

<?php
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$getpath=explode("/",$actual_link);
echo end($getpath);
?>

Short Explanation :

Step 1 : Get the url by

http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]

Step 2 : Explode with slash

explode("/",$actual_link)

Step 3 : Get the last part

end($getpath);

answered Apr 10 '15 at 09:23

Sulthan Allaudeen

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Works perfectly, with a great explanation! – Ibrahim Apr 10 '15 at 09:41

score 0 · Accepted Answer · answered Apr 10 '15 at 09:23

0

Try this..

<?php
$data = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$whatIWant = explode("/",$data);
 echo end($whatIWant);?>

answered Apr 10 '15 at 09:23

Deenadhayalan Manoharan

5,436
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@Jocker *it is help ful means accept my answer* NO! This doesn't mean that OP has to accept exactly your answer. Maybe an upV because that's what the tooltip says: *This answer is useful*; There is a good post on meta how accepting works and which may helps OP to decide which answer he can/should choose/accept: http://meta.stackexchange.com/q/5234 – Rizier123 Apr 10 '15 at 09:32

score 0 · Answer 3 · answered Apr 10 '15 at 09:25

0

You can also try it this way using strrchr :

$url = 'http://spiritofethiopia.com/test/test/test/index.php';
$str = substr(strrchr($url, '/'), 1);
echo $str;

strrchr — Find the last occurrence of a character in a string.

answered Apr 10 '15 at 09:25

Jenis Patel

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This works, but i don't want to place the url manually to all my pages – Ibrahim Apr 10 '15 at 09:28
you can also use the `$_SERVER['REQUEST_URI']` instead of manual url. I just used manual url for providing you an example. – Jenis Patel Apr 10 '15 at 09:33

Madhu · Answer 4 · 2015-04-10T09:32:04.817

0

Try This:

working solution,

<?php 

  $url = 'http://test/test/test/index.php';
  $tokens = explode('/', $url);
  echo $tokens[sizeof($tokens)-1];

?>

edited Apr 10 '15 at 09:32

answered Apr 10 '15 at 09:27

Madhu

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if string contain more slashes.your code did'nt work at all. – Alive to die - Anant Apr 10 '15 at 09:27
@anantkumarsingh I have corrected the answer – Madhu Apr 10 '15 at 09:33
@JenisPatel: It's working fine, I have checked with your url as well. – Madhu Apr 10 '15 at 09:50
I do not think so it works for you as you are using `substr($test,15)` you are giving a fixed position number `15` so for `$test = 'test/test/test/test/index.php';` the output will be `/test/index.php ` not `index.php` – Jenis Patel Apr 10 '15 at 09:56
@JenisPatel: I have changed my answer long back. – Madhu Apr 10 '15 at 09:58
1

Okay fine :) Just check your updated answer. – Jenis Patel Apr 10 '15 at 10:00
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/74917/discussion-between-madhu-and-jenis-patel). – Madhu Apr 10 '15 at 10:02

score 0 · Answer 5 · answered Apr 10 '15 at 09:27

You can use preg_match whith a correct RegExp to capture the end of the URL.

<?php
$data = $_SERVER['REQUEST_URI'];

if(preg_match('#/([^/]*?)$#', $data, $matches) == 1) {
    echo $matches[1];
}
else {
    // Should not happen
    /*
     * Throw exception
     */
}

?>

score 0 · Answer 6 · answered Apr 10 '15 at 09:29

0

Try strripos instead of strpos, it may works

<?php
    $data = $_SERVER['REQUEST_URI'];
    $whatIWant = substr($data, strripos($data, "/") + 1); 
        echo $whatIWant;
    ?>

answered Apr 10 '15 at 09:29

fba_pereira

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PHP: echo only the last part of a url, intead code printing the whole url

6 Answers6