Missing separator in my Makefile

Question

This is my structure:

Makefile
src/main.cpp
include/xml.hpp

My Makefile looks like this:

# Define compiler: gcc for C program, define as g++ for C++
CC = g++

# Compiler flags:
#  -g    adds debugging information to the executable file
#  -Wall turns on most, but not all, compiler warnings
CFLAGS  = -g -Wall

# Build target executable:
TARGET = main

all: $(TARGET)

$(TARGET): $(TARGET).c
  $(CC) $(CFLAGS) -o $(TARGET) $(TARGET).c

clean:
  $(RM) $(TARGET)

The error I get is this:

15 *** missing separator.  Stop.

I copied this code from a tutorial so I'm not sure where I have gone wrong.

Are the spaces before `$(CC)` and `$(RM)` a single tab character? or 2 spaces? — Bill Lynch, Apr 13 '15 at 17:21
General advice: it is always good idea to enable "Show whitespaces" option in your text editor — Ivan Aksamentov - Drop, Apr 13 '15 at 17:30
Did you even try to search for "makefile missing separator" before asking this question? — Jonathan Wakely, Apr 13 '15 at 17:30

score 3 · Accepted Answer · edited Apr 13 '15 at 17:30

3

You're using spaces instead of tabs.

The parser doesn't like that.

edited Apr 13 '15 at 17:30

Jonathan Wakely

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answered Apr 13 '15 at 17:24

deW1

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Missing separator in my Makefile

1 Answers1