User input integer list

Question

I am trying to create a piece of code that allows me to ask the user to enter 5 numbers at once that will be stored into a list. For instance the code would would be ran and something like this would appear in the shell

Please enter five numbers separated by a single space only:

To which the user could reply like this

 1 2 3 4 5

And then the numbers 1 2 3 4 5 would be stored into a list as integer values that could be called on later in the program.

Have you tried something? – Eric Levieil Apr 13 '15 at 21:22 — Eric Levieil, Apr 13 '15 at 21:22
This looks a lot like a homework question. – Leon Frickenschmidt Dec 10 '16 at 03:27 — Leon Frickenschmidt, Dec 10 '16 at 03:27

score 1 · Answer 1 · answered Apr 13 '15 at 21:23

1

You can use something like this:

my_list = input("Please enter five numbers separated by a single space only")
my_list = my_list.split(' ')

answered Apr 13 '15 at 21:23

Now how do you turn the numbers you input into integers? – FCBHokie Apr 13 '15 at 21:25
Both mine and Daniel's answer will return a list of integers rather than a list of integer *strings*. @FCBHokie – Zach Gates Apr 13 '15 at 21:27

score 1 · Accepted Answer · answered Apr 13 '15 at 21:24

Your best way of doing this, is probably going to be a list comprehension.

user_input = raw_input("Please enter five numbers separated by a single space only: ")
input_numbers = [int(i) for i in user_input.split(' ') if i.isdigit()]

This will split the user's input at the spaces, and create an integer list.

score 0 · Answer 3 · answered Apr 13 '15 at 21:25

0

This could be achieved very easily by using the raw_input() function and then convert them to a list of string using split() and map()

num = map(int,raw_input("enter five numbers separated by a single space only" ).split())
[1, 2, 3, 4, 5]

answered Apr 13 '15 at 21:25

Daniel

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score 0 · Answer 4 · answered Apr 13 '15 at 21:29

0

You'll need to use regular expressions as the user may also enter non-integer values as well:

nums = [int(a) for a in re.findall(r'\d+', raw_input('Enter five integers: '))]
nums = nums if len(nums) <= 5 else nums[:5] # cut off the numbers to hold five

answered Apr 13 '15 at 21:29

Malik Brahimi

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You don't *need* to - if the user enters non-integers why *shouldn't* it fail? – jonrsharpe Apr 13 '15 at 21:31

score -1 · Answer 5 · edited Jun 04 '16 at 13:21

-1

Here is a subtle way to take user input into a list:

l=list()
while len(l) < 5: # any range
    test=input()
    i=int(test)
    l.append(i)

print(l)

It should be easy enough to understand. Any range range can be applied to the while loop, and simply request a number, one at a time.

edited Jun 04 '16 at 13:21

armatita

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answered Jun 04 '16 at 04:12

user3773786

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User input integer list

5 Answers5