How about method of var_dump($x) in php

Question

By the way i surprised about this What will this code output and why?

$x = true and false;
var_dump($x);

*What will this code output and why?* Why not just try it? – Rizier123 Apr 15 '15 at 11:22 — Rizier123, Apr 15 '15 at 11:22
Why don't you try it yourself? – Frank Apr 15 '15 at 11:22 — Frank, Apr 15 '15 at 11:22

score 7 · Accepted Answer · answered Apr 15 '15 at 11:24

Surprisingly to many, the above code will output bool(true) seeming to imply that the and operator is behaving instead as an or.

The issue here is that the = operator takes precedence over the and operator in order of operations, so the statement $x = true and false ends up being functionally equivalent to:

$x = true; // sets $x equal to true true and false; // results in false, but has no affect on anything This is, incidentally, a great example of why using parentheses to clearly specify your intent is generally a good practice, in any language. For example, if the above statement $x = true and false were replaced with $x = (true and false), then $x would be set to false as expected.

score 1 · Answer 2 · edited May 23 '17 at 11:59

1

As explained here, the = operator has higher precedence than the and operator, causing $x = true to evaluate before true and false does, meaning that $x will take the value of true.

This will give you what you want:

$x = (true and false);

edited May 23 '17 at 11:59

Community

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answered Apr 15 '15 at 11:25

Frank

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How about method of var_dump($x) in php

2 Answers2