Python selenium is_displayed method

Question

I want to be able to reach the else statement and not get an exceptions when the element is not displayed.

for example:

 if driver.find_element_by_xpath("/html/body/main/div/article[2]/div[4]/header/div[2]/div/div[3]/a[4]").is_displayed():
            print("yeah found it")
        else:
            print("not found")

i want to get to the else statement however when the element is not displayed then i will get an exception instead of print("not found") — user3671239, Apr 16 '15 at 19:05
i know there is no such element thats why i want it to print not found or in other case i want it to continue with the test — user3671239, Apr 16 '15 at 19:08

score 2 · Accepted Answer · edited May 23 '17 at 12:22

2

You CANNOT call is_displayed() or any other property on an element that does not exist. is_displayed() only would work if the element present in the DOM but hidden or displayed. your program is failing before even reaching the code to check if it is displayed or not. So the possible fix is probably to use some kind of try catch instead

from selenium.common.exceptions import NoSuchElementException

found = False
while not found:
    try:
        link = driver.find_element_by_xpath(linkAddress)
        found = True
    except NoSuchElementException:
        time.sleep(2)

Example code taken from here

edited May 23 '17 at 12:22

Community

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answered Apr 16 '15 at 19:12

Saifur

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This is not what am looking for, am looking for a way i can keep running the test without getting an exception even though the element i was looking for is not found. So if element is not found jump to the else statment and see whats in there to run – user3671239 Apr 16 '15 at 19:27
I am not sure if I am following you correctly. How would you keep running a test if the intended element is not found? – Saifur Apr 16 '15 at 19:28
1

never mind your answer was great i tweaked your code alittle bit and now its working fine thank u very much. – user3671239 Apr 16 '15 at 19:33

shuk · Answer 2 · 2017-07-09T11:04:12.867

I ran into the same issue and this Q&A block was the game changer. I tweaked the given code by Saifur too, to match my needs, which I believe similar to this question's request:

elementlist = []
found = False
while not found:
    try:
        element_ = browser.find_element_by_xpath("//*[@class='class' and (contains(text(),'Optional-text-contain'))]")
        if element_.is_displayed():
            value = element_.find_element_by_css_selector("*")
            elementlist.append(value.text)
            print("Element: " + value.text)
            found = True
    except NoSuchElementException:
        elementlist.append("N/A")
        print("Element: N/A")
        found = True

This code looks for an alternating element within the page (sometimes exists, sometimes doesn't). If it exists, it gives its' value. If not - it continues normally while appending the list a "NaN" style value, just to match axis for later DFing

Again, Saifur delivered enormous assistance in this issue. Thank you user3691239 for asking this question, and mentioning it worked for you after a lil' tweak.

Python selenium is_displayed method

2 Answers2