Creating a list that includes all integers between start and end in Python?

Question

If I have two integer (start, end),

for example,

start, end = 3,8

then I want to create a list that includes all integers from 3 to 8 (also includes 3 and 8)

[3,4,5,6,7,8]

How can I get that?

@TanveerAlam Answers should be posted as answers. – syntonym Apr 16 '15 at 20:15 — syntonym, Apr 16 '15 at 20:15
Go read a tutorial or the language docs. – Marcin Apr 16 '15 at 20:18 — Marcin, Apr 16 '15 at 20:18

score 6 · Accepted Answer · edited May 23 '17 at 12:28

6

Python 3: use range as the generator, and list to complete:

list(range(start, end+1))

For Python 2, take note of range vs xrange and that you'd need a call to list if you go the route of xrange, which acts the same as range in Python 3.

edited May 23 '17 at 12:28

Community

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answered Apr 16 '15 at 20:16

Celeo

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No need to make it a `list` since `range` returns a`list` – Daniel Apr 16 '15 at 20:19
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@DanielJimenez In Python 3, `range` is a generator: https://docs.python.org/3/library/stdtypes.html#range – Selcuk Apr 16 '15 at 20:22

score 0 · Answer 2 · answered Apr 16 '15 at 20:22

You can use built-in range function for it:

In python 2.x

>>> start, end = 3, 8
>>> range(start, end+1)
[3, 4, 5, 6, 7, 8]

In python 3.x you have to call list function on range to get list as range by itself returns generator object.

In [1]: start, end = 3, 8
In [2]: range(start, end+1)
Out[2]: range(3, 9)
In [3]: list(range(start, end+1))
Out[3]: [3, 4, 5, 6, 7, 8]

Creating a list that includes all integers between start and end in Python?

2 Answers2