Regex - Duplicate HTML links and put something after it

Question

I have a lot of such texts:

<a href="https://mega.co.nz/#![RandomThings1]" target="_blank">[RandomThings2] [<span style="color:#008000;">[RandomThings3]</span>]</a>

I want to transform those into this:

<a href="https://mega.co.nz/#![RandomThings1]" target="_blank">[RandomThings2] [<span style="color:#008000;">[RandomThings3]</span>]</a> <a href="http://no.refer.co/?link=https://mega.co.nz/%23![RandomThings1]" target="_blank">NoRefer</a>

How can I do this?

Are you trying to add another link after all that **RandomThings3** stuff? — Paweł Tomkiel, Apr 17 '15 at 19:57

score 0 · Accepted Answer · answered Apr 17 '15 at 20:50

0

Since the regex flavor in Search Regex WordPress plug-in is PHP, you can try the following regular expression that assumes you really have some arbitrary text inside square brackets ([RandomThings1]):

(<a\s+[^>]*?href="[^"]*#!(\[.*?\])"[^>]*?>[^<>]*?<span[^>]*?>[^<>]*?<\/span>[^<>]*?<\/a>)

Replace with $1 <a href="http://no.refer.co/?link=https://mega.co.nz/%23!$2" target="_blank">NoRefer</a>.

Here is a demo.

PHP code:

$re = "/(<a\\s+[^>]*?href=\"[^\"]*#!(\\[.*?\\])\"[^>]*?>[^<>]*?<span[^>]*?>[^<>]*?<\\/span>[^<>]*?<\\/a>)/"; 
$subst = "$1 <a href=\"http://no.refer.co/?link=https://mega.co.nz/%23!$2\" target=\"_blank\">NoRefer</a>"; 
$result = preg_replace($re, $subst, $str);

answered Apr 17 '15 at 20:50

Wiktor Stribiżew

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@Downvoter: I do not know what you found wrong, please report. Just downvoting will soon leave you without rep :) – Wiktor Stribiżew Apr 17 '15 at 21:55
it was not me, I will test the regex – Vaguiner Gonzalez Apr 17 '15 at 22:41
have worked, but i have to export my db and try to use in notpead++, and mofied something in this code – Vaguiner Gonzalez May 05 '15 at 21:14

Regex - Duplicate HTML links and put something after it

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