How do I split all the data in str in python?

Question

I have to split the values from a txt file. Problem is I can't split all the data and return. I don't even know which str method will accomplish my goal. Here's what I want to do:

Given data:

1.02.34.35.55.33.64.64.46.74.36.67.45.68.53.75.54.45.23.67.24.98.67.45.23.75.2

what I want:

1.0
2.3
4.3
5.5
.
.
.
.
.
5.2

how are you getting "given data"? can you post the code you're using to read the text file in order to define "given data"? also, post a few lines of the text file, as they appear in the file itself. — abcd, Apr 21 '15 at 19:22
Will all numbers always be exactly one digit followed by a decimal point followed by exactly one digit? If not, if you see "1.012.3", should that become "1.0 12.3", or "1.01 2.3"? — Kevin, Apr 21 '15 at 19:22
No i don't have that. All I'm getting is a text file containing those value. — Taha, Apr 21 '15 at 19:23
this question is total nonsense. why on earth would anyone ever save data in a text file that way? — abcd, Apr 21 '15 at 19:27
@dbliss Sometimes we don't decide, which format our data arrives in. — tommy.carstensen, Apr 22 '15 at 08:50

score 3 · Answer 1 · edited May 23 '17 at 11:57

3

chunk the string into groups of three, then re-join.

def chunks(l, n):
    """ Yield successive n-sized chunks from l.
    """
    for i in xrange(0, len(l), n):
        yield l[i:i+n]

s = '1.02.34.35.55.33.64.64.46.74.36.67.45.68.53.75.54.45.23.67.24.98.67.45.23.75.2'

print "\n".join(chunks(s,3))

Result:

1.0
2.3
4.3
5.5
...
5.2

edited May 23 '17 at 11:57

Community

1
1

answered Apr 21 '15 at 19:24

Kevin

74,910
12
133
166

score 2 · Answer 2 · answered Apr 21 '15 at 19:24

Perhaps the easiest answer is to split the string up 3 characters at a time. This assumes that each number is exactly two digits with a decimal point in between.

>>> data = '1.02.34.35.55.33.64.64.46.74.36.67.45.68.53.75.54.45.23.67.24.98.67.45.23.75.2'
>>> [data[i:i+3] for i in range(0, len(data), 3)]
['1.0', '2.3', '4.3', '5.5', '5.3', '3.6', '4.6', '4.4', '6.7', '4.3', '6.6', '7.4', '5.6', '8.5', '3.7', '5.5', '4.4', '5.2', '3.6', '7.2', '4.9', '8.6', '7.4', '5.2', '3.7', '5.2']

score 1 · Accepted Answer · answered Apr 21 '15 at 19:32

1

s = '1.02.34.35.55.33.64.64.46.74.36.67.45.68.53.75.54.45.23.67.24.98.67.45.23.75.2'
for i in range(0,len(s),3):
    print(s[i:i+3])

answered Apr 21 '15 at 19:32

tommy.carstensen

8,962
15
65
108

score 1 · Answer 4 · answered Apr 21 '15 at 19:41

You could also use regexp.

import re
test='1.02.34.35.55.33.64.64.46.74.36.67.45.68.53.75.54.45.23.67.24.98.67.45.23.75.2'
num = re.compile('\d\.\d')
list_of_num = re.findall(num, test)

Internally it does the same thing - the regex engine matches against each character. So can't say this is more performant. You don't have to look at loops though.

How do I split all the data in str in python?

4 Answers4