Count the occurence of a string in multidimentional array

Question

I'm trying to count the occurence of a string in multidimentional array and get it.

So I found this : http://php.net/manual/fr/function.array-count-values.php and an exemple in the "User Contributed Notes".

Here my code :

$count_values = array();
foreach ($Bigtable as $a)
{
    foreach ($a as $table)
    {
        $count_values[$table]++;             // line 32
    }
}
asort($count_values,SORT_NUMERIC );
$onet_code=end ($count_values);

Here my error: Notice: Undefined index: 11-1011.00 in /home/goldiman1/www/postQuestion.php on line 32

I think that the error is in the last line when I try to get the string.

What do you guys think about it?

Thank you

Goldiman

Edit: Thank you everybody for your help ! All solutions work like a charm and I understood what was the issue, it was easier to understand Kasia answer because i'm more familiar with isset()

This isn't possible if $count_value[$table] isn't an integer. — Jordy, Apr 22 '15 at 12:35
Arrggggggg, Thank you Jordy, Any suggestion what to do with a string? — goldiman, Apr 22 '15 at 12:36
Look at Tim's answer below, you should indeed check if the value is set, if it isn't set it to 1 if it is increment it by 1. — Jordy, Apr 22 '15 at 12:38

Tim B · Accepted Answer · 2015-04-22T12:36:58.817

4

$count_values[$table]++;

This line is trying to increment the value in $count_values[$table] - but you never initialize that value in the first place!

You need to change this code to create the value at 1 if it doesn't already exist, and only increment it if it does exist.

edited Apr 22 '15 at 12:36

answered Apr 22 '15 at 12:35

Tim B

40,716
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To complete: he should use isset before calling the ++ operator – Answers_Seeker Apr 22 '15 at 12:36
@Answers_Seeker I would use array_key_exists – Apr 22 '15 at 12:38
Right FPar, I learned something today: [link] (http://stackoverflow.com/questions/3210935/difference-between-isset-and-array-key-exists) – Answers_Seeker Apr 22 '15 at 12:50

score 2 · Answer 2 · answered Apr 22 '15 at 12:38

2

If $table exists on the array(key) then increment the value else create new one. Try this -

foreach ($Bigtable as $a)
{
    foreach ($a as $table)
    {
        if (array_key_exists($table, $count_values)) {
            $count_values[$table]++;
        } else {
            $count_values[$table] = 1;
        }
    }
}

answered Apr 22 '15 at 12:38

Sougata Bose

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1

I was trying to point him in the right direction without giving him the full solution. Still, this answer is more complete than mine so +1 :) – Tim B Apr 22 '15 at 12:43

score 1 · Answer 3 · answered Apr 22 '15 at 12:39

1

by default $count_values[$table] won't be set

foreach ($a as $table)
{
    if(isset($count_values[$table])){
        $count_values[$table]++;
    } else {
        $count_values[$table] =1
    }
}

answered Apr 22 '15 at 12:39

Kasia Gogolek

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Count the occurence of a string in multidimentional array

3 Answers3