C++ : What is the usage of int('0') in this code?

Question

This code Find the sum of all digits that occur in a string.

Example

sumUpNumbers("2 apples, 12 oranges") = 5 //2+1+2

Can anyone explain the need for use int('0') in this code!?

int sumUpDigits(std::string inputString) {

  int answer = 0;

  for (int i = 0; i < inputString.size(); i++) {  
    if ('1' <= inputString[i] && inputString[i] <= '9') {
      answer += int(inputString[i]) - int('0');
    }
  }

  return answer;
}

to clarify, `int(X)` is redundant in this code. The key point is `inputstring[i] - '0'`, which is covered by the duplicate; and there are redundant casts. Whoever wrote this code didn't know the language very well. — M.M, Apr 23 '15 at 00:16

score 1 · Answer 1 · answered Apr 22 '15 at 23:36

1

It converts char into ASCII code to make number out of string

int('9') - int('0') = 9

answered Apr 22 '15 at 23:36

Severin Pappadeux

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Why you used int('0') it has nonsense here since int('9') is 9 – Amr Ragaey Apr 22 '15 at 23:42
@user3289638 In my world `int('9')` is equal to 57 – Severin Pappadeux Apr 22 '15 at 23:44
@user3289638 see `http://www.asciitable.com/` – Severin Pappadeux Apr 22 '15 at 23:45
Oh, it's clear now to me thanks a lot Severin – Amr Ragaey Apr 22 '15 at 23:47

C++ : What is the usage of int('0') in this code?

1 Answers1