How to return two values in Python

Question

I have following code below.

class NameParser:

    def __init__(self):
        self.getName

    def getName(self, name):
        splitName = name.split(' ')
        surname = splitName.pop()
        for i in range(len(splitName)):
            print('Name: %s' % splitName[i])

        return('Surname: %s' % surname)


np = NameParser()

print(np.getName("ali opcode goren"))

# output: name: ali, name: opcode, surname: goren

How do i return two values? Like following code:

for i in range(len(splitName)):
    return('Name: %s' % splitName[i])

return('Surname: %s' % surname)

# output: name ali: (error) i want all values name, name, surname

I want all values but just one output. How can I solve this problem?

Not expected. Output for two return: ali goren. Output for one print and one return: ali opcode goren (i want this) — Ali, Apr 23 '15 at 18:14
`return "Name: %s, Name: %s, Surname: %s"%(splitName[0], splitName[1], splitName[2])` and need to do exception handling when some name is missing in the input string. — Vivek Sable, Apr 23 '15 at 18:20
@VivekSable thanks but this is manual. i want automatic. example: abc cb cde ffe ags dle like => split[0,1,2,3,4]. but your code not automatic. thanks for your help. — Ali, Apr 23 '15 at 18:26
just assign string variable before for loop `output=""` and iterate for loop and concatenate output in the for loop like `output = "%s Name %s,"%(output, splitname[i])` and last after for loop do `output = "%s Surname %s,"%(output, surname)` and return output — Vivek Sable, Apr 23 '15 at 18:30
no nee to iterate for loop by range method. we can use `for i in splitName:` also in `i` is item from the list. — Vivek Sable, Apr 23 '15 at 18:37
@VivekSable this is not true.... I knew it already, but I tried it again still not possible. — Martijn van Wezel, Apr 23 '15 at 18:45

Vivek Sable · Answer 1 · 2015-04-27T07:25:48.590

Split: Split name by space and then do list comprehension again to remove the empty string from the list.
POP: get last item from the list by pop() method and assign it to surname variable.
Exception Handling: Do exception handling during pop process. If the input is empty then this will raise an IndexError exception.
string concatenate: Iterate every Item from the list by for loop and assign the value to user_name variable.
Concatenate surname in string again.
Display result.

Demo:

class NameParser:
    def __init__(self):
        pass

    def getName(self, name):
        #- Spit name and again check for empty strings.
        splitName = [i.strip() for i in name.split(' ') if i.strip()]
        #- Get Surname. 
        try:
            surname = splitName.pop()
        except IndexError:
            print "Exception Name for processing in empty."
            return ""
        user_name = ""
        for i in splitName:
            user_name = "%s Name: %s,"%(user_name, i)
        user_name = user_name.strip()

        user_name = "%s Surname: %s"%(user_name, surname)
        return user_name


np = NameParser()
user_name = np.getName("ali      opcode       goren      abc")
print "user_name:", user_name

Output:

user_name: Name: ali, Name: opcode, Name: goren, Surname: abc

Martijn van Wezel · Accepted Answer · 2015-04-23T18:42:38.367

1

Try this:

class NameParser:

    def __init__(self):
        self.getName

    def getName(self, name):
        listy = [] # where the needed output is put in
        splitName = name.split(' ')

        for i in range(len(splitName)):
            if i==(len(splitName)-1):#when the last word is reach
                listy.append('Surname: '+ splitName[i])
            else:
              listy.append('Name: '+ splitName[i])


        return listy


nr = NameParser()

print(nr.getName("ali opcode goren"))

# output: name: ali, name: opcode, surname: goren

whithout loop:

class NameParser:

    def __init__(self):
        self.getName

    def getName(self, name):
        listy = [] # where the needed output is put in
        splitName = name.split(" ")
        listy ="Name",splitName[0],"Name",splitName[1],"Surname",splitName[2]



        return listy


nr = NameParser()

print(nr.getName("ali opcode goren"))

# output: name: ali, name: opcode, surname: goren

edited Apr 23 '15 at 18:42

answered Apr 23 '15 at 18:15

Martijn van Wezel

1,120
14
25

I'm sorry. Not working. Just output: Name: ali I want like: Name: ali, Name: opcode, Surname: goren if i use print, it's work. – Ali Apr 23 '15 at 18:19
Thanks i get "goren" :). I can't get other values. I can solve, I guess. – Ali Apr 23 '15 at 18:37
I add also another code for when you don't want a loop. You ask it in another comment. – Martijn van Wezel Apr 23 '15 at 18:39
@MartijnvanWezel: in second code why you define `listy = []` ? need this statement? – Vivek Sable Apr 23 '15 at 18:48
You always have to declare a list how big he will be. So to say he is empty in my code he will be declared. When you want to fill the list, use append this will add a *something what you want* to the list – Martijn van Wezel Apr 23 '15 at 18:52
@MartijnvanWezel: Second code: what is type of `listy` variable? – Vivek Sable Apr 24 '15 at 07:22
@VivekSable that is a list – Martijn van Wezel Apr 24 '15 at 11:46
@MartijnvanWezel: just print type of this variable. `print type(listy)` before return. – Vivek Sable Apr 24 '15 at 13:14
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/76188/discussion-between-vivek-sable-and-martijn-van-wezel). – Vivek Sable Apr 24 '15 at 15:10

score 1 · Answer 3 · answered Apr 23 '15 at 18:27

1

Try to use yield

class NameParser:

    def __init__(self):
        self.getName

    def getName(self, name):
        splitName = name.split(' ')
        surname = splitName.pop()
        for i in range(len(splitName)):
            yield ('Name: %s' % splitName[i])

        yield ('Surname: %s' % surname)


np = NameParser()

for i in (np.getName("ali opcode goren")):
    print i

answered Apr 23 '15 at 18:27

ahmed

5,430
1
20
36

Thanks it's work! :) How to use this code without your for loop? – Ali Apr 23 '15 at 18:33
Read [this question and its answers](http://stackoverflow.com/questions/231767/what-does-the-yield-keyword-do-in-python). Ali, to learn about `yield`. – Celeo Apr 23 '15 at 18:36

score 1 · Answer 4 · answered Apr 23 '15 at 18:39

1

you can just do this:

def getName(self, name):
    return name.split(' ')

It will return a tuple

def get_name(name):
   return name.split(' ')

>>> get_name("First Middle Last")
['First', 'Middle', 'Last']

answered Apr 23 '15 at 18:39

joel goldstick

4,393
6
30
46

score 0 · Answer 5 · answered Mar 01 '20 at 07:27

0

or you can try

class test():
    map = {}
    for i in range(10):
        map[f'{i}'] = i
    return map

answered Mar 01 '20 at 07:27

samuel161

221
3
2

How to return two values in Python

5 Answers5