If string is in another list, call on the next value in said list (Python 3)

Question

Let's say I have a value callfunc in list list1 that I want to call on the next value in the list, but only if callfunc is in list2 (it is). I have this code:

for instr in list1:
if instr in list2:
    eval(instr(list1[list1.index(instr)+1]))

And I get this error message:

eval(instr(list1[list1.index(instr)+1]))
TypeError: 'str' object is not callable

I'm trying to get the output as a function, not a string of:

callfunc(75)

That will, in the script, call callfunc on 75.

lists 1 and 2:

list1 = [callfunc, 75]
list2 = [callfunc]

I have no idea where to go from here. Help would be greatly appreciated.

callfunc is a string.

score 1 · Answer 1 · answered Apr 25 '15 at 02:00

1

I don't really understand why you use eval here. If you want to call the function, just do this:

for ifunc in list1:
if ifunc in list2:
    d = ifunc(list1[list1.index(ifunc)+1])
    print(d)

answered Apr 25 '15 at 02:00

ljk321

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Returning: TypeError: 'str' object is not callable. I'm a noob at this and I really don't know why it's returning this. – Gavyn Rogers Apr 25 '15 at 02:08
Is `callfunc` really a function? – ljk321 Apr 25 '15 at 02:09
...it's always the simplest things, isn't it? No, it's a string. – Gavyn Rogers Apr 25 '15 at 02:10
It a string? In both the list? – ljk321 Apr 25 '15 at 02:11
Why bother? I mean, you could totally put a function in the list, and it should work with my code above. – ljk321 Apr 25 '15 at 02:13

score 0 · Accepted Answer · edited May 23 '17 at 12:22

0

Try:

eval(instr+"("+list1[list1.index(instr)+1]+")")

This will create the call string you wanted.

Then read this question and it's answers.

edited May 23 '17 at 12:22

Community

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answered Apr 25 '15 at 01:58

Reut Sharabani

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If string is in another list, call on the next value in said list (Python 3)

2 Answers2