Given this file
printf 'alpha\0bravo\0charlie' > delta.txt
I would like to read the fields into separate variables. The reason I am using a null separator is because the fields will contain file paths, which can contain any character except null. I tried these commands:
IFS= read mike november oscar < delta.txt
IFS=$'\0' read mike november oscar < delta.txt
However the fields are not being properly split
$ echo $mike
alphabravocharlie
The assignment IFS=$'\0' doesn't make the null character a delimiter, since Bash variables cannot hold null characters. IFS=$'\0' is equivalent to IFS=, which you can verify by doing:
bash-4.3$ IFS=$'\0'
bash-4.3$ echo ${#IFS}
0
And IFS= by definition means no word splitting at all (see Bash Reference Manual).
What you can do is read the null delimited items one by one using the -d option of the read builtin. According to linked documentation,
-d delimThe first character of
delimis used to terminate the input line, rather than newline.
We can use a null string for delim to get desired behavior.
Example (I took the liberty to add whitespace to your example to demonstrate how it achieves what to want — no splitting on whitespace):
bash-4.3$ printf 'alpha with whitespace\0bravo with whitespace\0charlie with whitespace' > delta.txt
bash-4.3$ { read -r -d '' mike; IFS= read -r -d '' november; IFS= read -r -d '' oscar; echo $mike; echo $november; echo $oscar; } < delta.txt
alpha with whitespace
bravo with whitespace
charlie with whitespace
I'm also using the -r option to preserve backslashes in the input file. Of course you can replace < delta.txt with a cat delta.txt | at the beginning.
I know reading one by one is annoying, but I can't think of anything better.
As a workaround, I created this function
function read_loop {
while [ "$#" -gt 0 ]
do
read -d '' "$1"
shift
done
}
Example use
read-nul mike november oscar < delta.txt