How to get client Ip Address in Java HttpServletRequest

Question

I am trying to develop a Java web application (Servlet) which I need to get clients IP address.

Following is my code so far:

String ipAddress =  request.getRemoteAddr();

In this case most of the time I get the 'Default gateway address' (147.120.1.5). Not my machine IP address(174.120.100.17).

String ipAddress = request.getHeader("X-FORWARDED-FOR");  
if (ipAddress == null) {  
    ipAddress = request.getRemoteAddr();  
}

In this case most of the time I get the 'Default gateway address' (147.120.1.5). Not my machine IP address (174.120.100.17).

InetAddress IP=InetAddress.getLocalHost();
System.out.println(IP.getHostAddress());

In this case I got the server IP Address (147.120.20.1).

My IP address in 147.120.100.17. Now I don't know how to get the real client IP address.

Thank you very much.

There is no accurate way to get the client ip address unless the client explicitly sends it to you — Scary Wombat, Apr 28 '15 at 04:10
There is not way to get the client's real Ip address what you actually see there is your public IP address. — Rod_Algonquin, Apr 28 '15 at 04:11
possible duplicate of [Is it possible to accurately determine the IP address of a client in java servlet](http://stackoverflow.com/questions/9326138/is-it-possible-to-accurately-determine-the-ip-address-of-a-client-in-java-servle) — YoYo, Apr 28 '15 at 04:17
It means there are no way for a web app to accurately determine the client IP address????? — Samith Dilshan, Apr 28 '15 at 04:30
The last option is wrong. It returns the ip of your server. You think its correct because in a development environment, your server and the browser you test it from are co-located. — ramp, Apr 28 '15 at 10:59

score 89 · Accepted Answer · edited Jan 08 '20 at 12:41

89

Try this one,

String ipAddress = request.getHeader("X-FORWARDED-FOR");  
if (ipAddress == null) {  
    ipAddress = request.getRemoteAddr();  
}

reference : http://www.mkyong.com/java/how-to-get-client-ip-address-in-java/

edited Jan 08 '20 at 12:41

Max

915
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28

answered Apr 28 '15 at 05:21

gihan-maduranga

4,381
5
41
74

6

When I use the above code, I'm getting 'localhost' not my ip address. – Rama Krishna Jul 28 '17 at 06:33
38

X-FORWARD-FOR header is a bit risky here. Because if you use reverse proxy for request, this header value will be like this: 231.23.45.65, 10.20.10.33, 10.20.20.34 (which means client ip, load balancer server, reverse proxy server). Check if your X-FORWARD-FOR header value contains ',' or not. `ipAddress.contains(",") ? ipAddress.split(",")[0] : ipAddress` – utkusonmez Aug 23 '17 at 07:14
Agreed. Reasonable reference (as of 2023 March) is here: https://developer.mozilla.org/en-US/docs/Web/HTTP/Headers/X-Forwarded-For – Scott Corscadden Mar 08 '23 at 17:23

score 32 · Answer 2 · edited Jan 08 '20 at 12:42

Try this one. for all condition

private static final String[] HEADERS_TO_TRY = {
            "X-Forwarded-For",
            "Proxy-Client-IP",
            "WL-Proxy-Client-IP",
            "HTTP_X_FORWARDED_FOR",
            "HTTP_X_FORWARDED",
            "HTTP_X_CLUSTER_CLIENT_IP",
            "HTTP_CLIENT_IP",
            "HTTP_FORWARDED_FOR",
            "HTTP_FORWARDED",
            "HTTP_VIA",
            "REMOTE_ADDR" };

private String getClientIpAddress(HttpServletRequest request) {
    for (String header : HEADERS_TO_TRY) {
        String ip = request.getHeader(header);
        if (ip != null && ip.length() != 0 && !"unknown".equalsIgnoreCase(ip)) {
            return ip;
        }
    }

    return request.getRemoteAddr();
}

It's always a good idea to add some explanation to an answer so the OP can actually learn something. — trotta, Jul 07 '19 at 08:46

score 2 · Answer 3 · edited Mar 21 '18 at 04:28

2

In case, you are trying to get the IP-address for Dev-environment then you can use this:-

public String processRegistrationForm(HttpServletRequest request)
{
    String appUrl = request.getScheme() + "://"+ request.getLocalAddr();
    return appUrl;
}

The request.getLocalAddr() will return the IP-address of the request receiving system.

Hope it helps.

edited Mar 21 '18 at 04:28

sajas

1,599
1
17
39

answered Mar 21 '18 at 03:50

Partha Mondal

31
3

score -5 · Answer 4 · edited Dec 14 '16 at 07:45

 import java.net.UnknownHostException;

/**
 * Simple Java program to find IP Address of localhost. This program uses
 * InetAddress from java.net package to find IP address.
 *
 */
public class IPTest { 

public static void main(String args[]) throws UnknownHostException {

    InetAddress addr = InetAddress.getLocalHost();

    //Getting IPAddress of localhost - getHostAddress return IP Address
    // in textual format
    String ipAddress = addr.getHostAddress();

    System.out.println("IP address of localhost from Java Program: " + ipAddress);

    //Hostname
    String hostname = addr.getHostName();
    System.out.println("Name of hostname : " + hostname);     
}
}

Output:

IP address of localhost from Java Program: 190.12.209.123
Name of hostname : PCLOND3433

This does not answer the question. Question is about client ip address not servers (localhost). — Aniket Thakur, Jan 14 '17 at 08:16

How to get client Ip Address in Java HttpServletRequest

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