Program(java) skips nextLine() prompt and continues with program

Question

here is the code:

import java.util.Scanner;

public class DriverProject1
{
public static void main(String[] args)
{

    int roomNumber;
    int numberOfRooms;
    int optionNumber;
    String guestName = null;
    String phoneNumber;
    int nightsStaying;
    double nightlyRate;

    Scanner keyboard = new Scanner(System.in);
    System.out.println("How many rooms are in the hotel?");
    numberOfRooms = keyboard.nextInt();
    Hotel Carnegie = new Hotel(numberOfRooms);
    do
    {
        System.out.println("Welcome to the MENU!");
        System.out.println("Please enter a number corresponding to the option desired."); // main menu screen
        System.out.println("OPTION 1: Put guest into room");
        System.out.println("OPTION 2: Remove guest from room");
        System.out.println("OPTION 3: Get guest info");
        System.out.println("OPTION 4: Get guest count");
        System.out.println("OPTION 5: Display guest book");
        System.out.println("OPTION 6: Calculate expected income");
        System.out.println("OPTION 7: Quit");

        optionNumber = keyboard.nextInt(); // choosing an option
        if (optionNumber == 1) // if option 1 is chosen
        {

            System.out.println("What is the guests first name?");
            guestName = keyboard.nextLine();
            System.out.println("What is the guests Phone number?");
            phoneNumber = keyboard.nextLine();
            Guest newGuest = new Guest(guestName);
            newGuest.setPhoneNumber(phoneNumber);

"What is the guests first name? What is the guests Phone number?" appears and it will not take anything for the guest name. guestName has been initialized to "". lines 36 -39. not sure of the issue going on. i am using a few methods contained within my hotel class, however i am almost certain they do not contain the error which causes this bug. also the do loop is completed later on in the code.

-> Can you give us some more informations? I don't understand your problem — Lukas Hieronimus Adler, Apr 28 '15 at 06:26
Are you using anything apart from `nextLine()` for example `nextInt()` , `nextDouble()` etc in your program? — TheLostMind, Apr 28 '15 at 06:28
guestName is taking a value, but it is not being assigned to the name of newGuest because it happens after the input is taken — nitegazer2003, Apr 28 '15 at 06:28
when i run the program it prints the first two lines (What is the guests first name? & What is the guests Phone number?) . it does not stop to allow the user to enter a name for the guest. — Will, Apr 28 '15 at 06:29
skip a line after `nextInt()` because it doesnt consume the whole line — singhakash, Apr 28 '15 at 06:49
@Will - change the code as shown in my answer, then it will work properly — Fathah Rehman P, Apr 28 '15 at 09:32

score 0 · Accepted Answer · edited Apr 28 '15 at 09:06

0

keyboard.nextLine();
guestName = keyboard.nextLine();

Skip a line by adding keyboard.nextLine(); before reading guestname. This works for me.

edited Apr 28 '15 at 09:06

Siguza

21,155
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answered Apr 28 '15 at 08:15

Mohan Raj

1,104
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Fathah Rehman P · Answer 2 · 2015-04-28T09:32:22.093

change the code as shown below then it will work

import java.util.Scanner;

public class DriverProject1
{
public static void main(String[] args)
{

    int roomNumber;
    int numberOfRooms;
    int optionNumber;
    String guestName = null;
    String phoneNumber;
    int nightsStaying;
    double nightlyRate;

    Scanner keyboard = new Scanner(System.in);
    System.out.println("How many rooms are in the hotel?");
    numberOfRooms = Integer.parseInt(keyboard.nextLine());
    Hotel Carnegie = new Hotel(numberOfRooms);
    do
    {
        System.out.println("Welcome to the MENU!");
        System.out.println("Please enter a number corresponding to the option desired."); // main menu screen
        System.out.println("OPTION 1: Put guest into room");
        System.out.println("OPTION 2: Remove guest from room");
        System.out.println("OPTION 3: Get guest info");
        System.out.println("OPTION 4: Get guest count");
        System.out.println("OPTION 5: Display guest book");
        System.out.println("OPTION 6: Calculate expected income");
        System.out.println("OPTION 7: Quit");

        optionNumber = Integer.parseInt(keyboard.nextLine());; // choosing an option
        if (optionNumber == 1) // if option 1 is chosen
        {

            System.out.println("What is the guests first name?");
            guestName = keyboard.nextLine();
            System.out.println("What is the guests Phone number?");
            phoneNumber = keyboard.nextLine();
            Guest newGuest = new Guest(guestName);
            newGuest.setPhoneNumber(phoneNumber);

Program(java) skips nextLine() prompt and continues with program

2 Answers2