How can load image from MySQL database in NivoSlider. I can't seem to find a solution to this. I would like to create a jQuery image slider. I need to dynamically load images stored on my MYSQL database.
Any suggestions would be appreciated.
Here is my script:
</script></div>
<div class="jquery-script-clear"></div>
</div>
</div>
<h1 style="margin-top:150px;" align="center">jQuery Nivo Slider Demo</h1>
<div id="wrapper">
<div class="slider-wrapper theme-default">
<div id="slider" class="nivoSlider">
<?php
$connection = mysql_connect("localhost", "root", ""); // Establishing Connection with Server
$db = mysql_select_db("user"); // Selecting Database
$sql = mysql_query("SELECT * FROM images ORDER BY image DESC LIMIT 10") or die(mysql_error());
while($row = mysql_fetch_array($sql)){
$image = $row['image'];
$id = $row['id'];
$pic = "upload/$image";
if (file_exists($pic)) {
print '<img src=\"upload/$image\"/>';
$i++;
}
}
?>
</div>
</div>
</div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="jquery.nivo.slider.js"></script>
<script type="text/javascript">
$(window).load(function() {
$('#slider').nivoSlider();
});
</script>
<script type="text/javascript">
var _gaq = _gaq || [];
_gaq.push(['_setAccount', 'UA-36251023-1']);
_gaq.push(['_setDomainName', 'jqueryscript.net']);
_gaq.push(['_trackPageview']);
(function() {
var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true;
ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js';
var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s);
})();
</script>
Updated code:
<?php
$connection = mysql_connect("localhost", "root", ""); // Establishing Connection with Server
$db = mysql_select_db("user"); // Selecting Database
$sql = mysql_query("SELECT * FROM images ORDER BY image DESC LIMIT 10")or die(mysql_error());
while($row = mysql_fetch_array($sql)){
$image = $row['image'];
$id = $row['id'];
$pic = "upload/".$image";
if (file_exists($pic)) {
print '<img src=\"upload/$image\"/>';
$i++;
}
}
?>