Printing entire line till END of LINE using grep

Question

I am having the following piece of text.

TRACE(FOO, CAT,
    INFO, "Hello World")

If I use grep -r "FOO" file.txt, grep only prints the first line. I need the whole line to be matched. I only have FOO as the search key. I want to do this with grep.

I tried grep --after-context=1, but in cases where my test is TRACE(FOO, CAT, INFO, "HELLO WORLD" (i.e no line break after the CAT) it is unnecessarily showing the next line too.

Can you please help me with doing it.

Chid

What do you mean by whole line? those two are different lines... — Jahid, Apr 30 '15 at 00:28

Dyno Fu · Accepted Answer · 2015-04-30T01:00:24.980

2

sed -n -e '/FOO.*)/p' -e '/FOO[^)]*$/{p;n;p}' x.txt

if sed is also acceptable. and -n quiet the output, p print the line, n goes to the next line.

combine the 2 lines,

 sed -n -e '/FOO.*)/p' -e '/FOO[^)]*$/{N;s/\n//p;n;p}' x.txt

edited Apr 30 '15 at 01:00

answered Apr 30 '15 at 00:34

Dyno Fu

8,753
4
39
64

thanks. Is there a way to concatenate them and print it as a same line – CHID Apr 30 '15 at 00:51
1

@CHID Sure. Just replace {p;n;p} with {N;s/\n */ /;p} – ooga Apr 30 '15 at 00:59

Printing entire line till END of LINE using grep

1 Answers1