In my iPhone / iPad app I am showing a UIDatePicker for time. It will display time in this format, 11:00 AM. When User clicks on the time row we expand the time row to display this datePicker row. I have a time stamp in string "starts": "11:00", // time of day in ISO-8601 format I need to show this on the picker wheel as selected time when it gets opened up. For this, first of all I get the date at 12 AM using https://stackoverflow.com/a/9040554/4082792. Then I convert the given time (11:00) to number of seconds and add it to the midnight time to get the current time. This time is in local timezone (as I specify the timezone while using NSDateFormatter). When I try to setDate to UIDatePicker with this date, It gives me incorrect time, even though the time is correct in the NSDate variable. For 11:00 AM, it gives me 6:40 while the local time is 4:30. So, I have two questions : 1) Why is the time wrong on wheel. 2) How can I convert the NSDate from one timezone to another, I need to show it in the local time format.
Snippet :
NSString *strDate = @"11:00";
NSDate *date = [NSDate date];
NSCalendar *calendar = [NSCalendar autoupdatingCurrentCalendar];
NSUInteger preservedComponents = (NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit);
date = [calendar dateFromComponents:[calendar components:preservedComponents fromDate:date]];
///Start time
NSString *startTime = @"11:00";
NSArray *startTimeSeparatedByColon = [startTime componentsSeparatedByString:@":"]; /// From 22:10 to [22, 10];
NSInteger hourPartOfStart = startTimeSeparatedByColon[0] ? [startTimeSeparatedByColon[0] integerValue] : 0;
NSInteger minutePartOfStart = startTimeSeparatedByColon[1] ? [startTimeSeparatedByColon[1] integerValue] : 0;
NSTimeInterval totalTime = (hourPartOfStart*60*60+minutePartOfStart*60);
NSDate *finalDate = [NSDate dateWithTimeInterval:totalTime sinceDate:date];
NSDate *dt = [NSDate dateWithTimeInterval:[NSTimeZone localTimeZone].secondsFromGMT sinceDate:finalDate];
self.datePicker.date = dt;