Symfony 2.6 logout back button (CakePHP)

Question

After trying a lot of different ways (success handler, cache directives, changing routes, overriding methods, etc.) I haven't been able to logout a user (using the FOSUserBundle) disabling her to see previous pages when pressing the back-button of the browser.

Is there a way to do it in Symfony 2.6?

In CakePHP this works perfectly in a Controller

public function logout() {

    session_destroy();
    $this->Auth->deny('*');
    $this->Auth->shutdown('*');
    $this->Session->setFlash('Logout succesful - no back button issue.');
    return $this->redirect($this->Auth->logout());

}

score 1 · Answer 1 · edited Jul 31 '18 at 12:18

1

Add the following headers to the top of the page in your application:

 header("Cache-Control: no-cache, no-store, must-revalidate"); 
 header("Pragma: no-cache");
 header("Expires: 0");

edited Jul 31 '18 at 12:18

Dean Meehan

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answered Jul 31 '18 at 11:14

A_S

127
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score 0 · Answer 2 · answered May 04 '15 at 20:38

0

You can redirect to logout page:

return $this->redirectToRoute('fos_user_security_logout');

answered May 04 '15 at 20:38

Aistis

3,695
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score 0 · Answer 3 · edited May 23 '17 at 10:30

0

You need to send no-cache directive to the browser Try this solution https://stackoverflow.com/a/41566590/1154919

edited May 23 '17 at 10:30

Community

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answered Jan 10 '17 at 10:33

Yuriy Yakubskiy

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Symfony 2.6 logout back button (CakePHP)

3 Answers3