Finding sqrt of big integers in python

Asked May 01 '15 at 16:56

Active May 01 '15 at 17:10

Viewed 68 times

I have problems with rounding big numbers. My code:

import math
n = int(input())
print (int(math.floor(math.sqrt(n))))

Input:

10000000000000000000000000000000000000000000000000000000000000000000000000000

Output:

99999999999999997748809823456034029568

How can i solve the problem? Sorry for my English!!!

asked May 01 '15 at 16:56

Rasul Kerimov

2

See http://stackoverflow.com/questions/15390807/integer-square-root-in-python – netvope May 01 '15 at 16:59
Use the [`decimal` module](https://docs.python.org/2/library/decimal.html). – Mark Ransom May 01 '15 at 16:59

0 Answers0