Store on PHP variables sent by Ajax

Question

I am creating a DDBB Insert trough $.ajax:

$(document).on('click','.submitMessage', function(){
    content=$('textarea').val();
    img=$('#messageImg').val();
    stdMsg=$('.ms_stdMsg').val();
    prefix=$('.prefix').val();
    phone=$('.cuadroTelefono').val();

    $.ajax({
        url: "../actions/newMessage.php",
        type: "POST", 
        data:{ms_content:content, ms_img:img,ms_prefix:prefix,ms_phone:phone},
        contentType: false, 
        cache: false,  
        processData:false, 
        success: function(data) 
        {   
            alert("Enviado");
        }
    });
});

And this is the way I receive code on newMessage.php:

$ms_content = $_POST['ms_content'];
$ms_img = $_POST['ms_img'];
$ms_prefix = $_POST['ms_prefix'];
$ms_phone = $_POST['ms_phone'];

Console gives an error

Notice: Undefined index: ms_content in C:...\newMessage.php on line 9

one for each variable passed (I have ommited entire URL)

As the posted information is an object, I guess I must decode it someway on PHP, but trying:

$ms_content = json_decode($_POST['ms_content']);

...has neither workd

That wouldn't be necessary if there was only one textarea @Vicky — Jay Blanchard, May 04 '15 at 12:09
Have you watched the request / response in the browser's console? Did you realize you're putting the same info in `$ms_content` and `$ms_img`? BTW, an image will not upload via AJAX like this, you're not trying to do that are you? Do you have any errors in your console (like not declaring `var` before each variable? — Jay Blanchard, May 04 '15 at 12:11
@JayBlanchard, image is preuploaded. This passes only its URL. I have setted correclty the duplicity of ms_content on PHP. — Biomehanika, May 04 '15 at 12:17
@JayBlanchard yes. I have alerted all variables before sending and all do have their content. — Biomehanika, May 04 '15 at 12:21
Do you see `content` being passed in the request / response window? — Jay Blanchard, May 04 '15 at 12:21
Nope. On the window it says an object is being posted: [object Object] — Biomehanika, May 04 '15 at 12:22
Do a `var_dump($_POST['ms_content'])` in your PHP to see what you get. — Jay Blanchard, May 04 '15 at 12:24
Open the Network tab of your console (F12 is all major browsers) and watch the AJAX request. Make sure you're seeing all your variables being posted — Machavity, May 04 '15 at 12:24
@Machavity I dont see them, only OBJECT. Please read messages before. — Biomehanika, May 04 '15 at 12:25
@JayBlanchard I have alerted the result of the var_dump and it gives back the entire ms_content string. So it catches it correclty. — Biomehanika, May 04 '15 at 12:26
An `alert()` doesn't work in the PHP code. What do you mean you "alerted the result"? And what is Line 9? — Jay Blanchard, May 04 '15 at 12:28
I have setted an echo with the var_dump on PHP, stored it on the $ajax response (data) and alerted it — Biomehanika, May 04 '15 at 12:28
Line 9 is the line from the file newMessage.php where is the variable value storing: $ms_content = $_POST['ms_content']; — Biomehanika, May 04 '15 at 12:29
Change `contentType: false` to `contentType: text` in your AJAX function. — Jay Blanchard, May 04 '15 at 12:41
I have tried dataType : "text", also combined with contentType: "application/json" but none of these gave me result. I keep looking for this, here must be the issue — Biomehanika, May 04 '15 at 12:51
@JayBlanchard solved: $.post('../actions/newMessage.php',{ms_content:content, ms_img:img,ms_prefix:prefix,ms_phone:phone}) — Biomehanika, May 04 '15 at 14:01
That is what you have in your original post. How is that different? — Jay Blanchard, May 04 '15 at 14:04
there are many differences: it is $.post, it only has url and data, etc... After trying hundreds of variations this worked for me — Biomehanika, May 04 '15 at 14:09

score 1 · Answer 1 · edited May 23 '17 at 12:21

1

You need to specify the data that you are sending with contentType parameter. For more references

edited May 23 '17 at 12:21

Community

1
1

answered May 04 '15 at 12:36

SpongePablo

870
10
24

I am about to check this. Thank you. – Biomehanika May 04 '15 at 12:39

score 0 · Answer 2 · edited May 06 '15 at 14:00

    $(document).on('click','.submitMessage', function(){
        content=$('textarea').val();
        img=$('#messageImg').val();
        stdMsg=$('.ms_stdMsg').val();
        prefix=$('.prefix').val();
        phone=$('.cuadroTelefono').val();

        $.ajax({
            url: "../actions/newMessage.php",
            type: "POST", 
            data:{ms_content:content, ms_img:img,ms_prefix:prefix,ms_phone:phone},
            cache: false,              
            success: function(data) 
            {   
                alert("Enviado");
            }
        });
    });

Please remove processData:false, contentType: false and then try.

score -1 · Answer 3 · answered May 04 '15 at 14:51

-1

You can use this $_REQUEST instead of $_POST in your php file.

$ms_content = $_REQUEST['ms_content'];

Instead of

$ms_content = $_POST['ms_content'];

Second Maybe due to url path

try giving full url path.

Third

Provide a contentType.

answered May 04 '15 at 14:51

user3612872

41
2

score -2 · Answer 4 · answered May 04 '15 at 12:16

-2

I think you have to access the $_GET parameters because jquery documentation says:

data Type: PlainObject or String or Array Data to be sent to the server. It is converted to a query string, if not already a string. It's appended to the url for GET-requests. See processData option to prevent this automatic processing. Object must be Key/Value pairs. If value is an Array, jQuery serializes multiple values with same key based on the value of the traditional setting (described below).

http://api.jquery.com/jquery.ajax/

So you will get your data with

$ms_img = $_GET['ms_img'];

answered May 04 '15 at 12:16

Rene Vorndran

693
1
6
13

Hi Rene.- No, there's a POST way to get this info. – Biomehanika May 04 '15 at 12:19
On the page you linked check out **method** and you'll see you can set AJAX to POST, which he did. **type** is the older way of doing it – Machavity May 04 '15 at 12:21
Okay i think i missinterpreted the description to only append it to the GET-request, but if i read it again, one could interpret it that only for GET-requests its appended to the url – Rene Vorndran May 04 '15 at 12:23
The comment you're referring to is there to let you know how it will behave in `GET` situations. Regardless, it's not an answer to the OP – Machavity May 04 '15 at 12:30

Store on PHP variables sent by Ajax

4 Answers4