Executing php script in perl with GET variables in url

Question

I have a perl script that executes a php script:

my $phpOutput = `/usr/bin/php /bart/bart.php`;

this works perfectly fine. now i want to add some variables to the url.

my $phpOutput = `/usr/bin/php /bart/bart.php?data=1`;

this fails.

Could not open input file: /bart/bart.php?data=1

any ideas why?

That looks like it is just executing it in the shell. Cant use http://php.net/manual/en/reserved.variables.argv.php? — chris85, May 08 '15 at 20:43
[This answer](http://stackoverflow.com/a/17724485/2734189) has kind of an interesting way to handle this. But it looks like you will need to change the PHP script one way or another to be able to handle calling it this way. — Don't Panic, May 08 '15 at 20:55

score 5 · Accepted Answer · answered May 08 '15 at 20:44

5

The ?x=y syntax is for web servers, whereas the CLI expects arguments separated by space after the filename. The way you've written it, PHP thinks that ?data=1 is part of the filename.

You could do

my $phpOutput = `/usr/bin/php /bart/bart.php 1`;

and use the $argv array to retrieve the argument 1 from within the PHP script. Since it's the first argument, it would be $argv[1] (the 0th index is the script name).

answered May 08 '15 at 20:44

Joel Hinz

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ok, thank you. Now what if that "1" is a variable....my $phpOutput = `/usr/bin/php /bart/bart.php $someVar`; would this work? – bart2puck May 08 '15 at 21:37
Sure, I see no reason it shouldn't. – Joel Hinz May 09 '15 at 22:16

Executing php script in perl with GET variables in url

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