Difference between python's parameters '', 'args', '', 'kwargs'

Asked May 12 '15 at 12:25

Active May 12 '15 at 12:25

Viewed 55 times

I am new to Python and Django framework. I found '*', '*args', '**', '**kwargs' as parameters in init method or in other methods. like given below.

def __init__(self, *args, **kwargs):
    super(RestRouter, self).__init__(*args, **kwargs)

I am quite unable to understand how to pass these parameters and which one is suitable in which condition? Can anyone explain me in brief with a good example for each parameter?

asked May 12 '15 at 12:25

Nishant Upadhyay

This is basic python. `*` is not a parameter by the way, it is an operator. – Malik Brahimi May 12 '15 at 12:27
`*args` is a variable amount of parameters. For example, `fun(*names)` could contain as many names as desired passed in the function like `func('Bob', 'Sam', 'Jon')`. – Malik Brahimi May 12 '15 at 12:29
Actually I was asking for *params and **params. I know that * is operator. – Nishant Upadhyay May 12 '15 at 12:29
`**kwargs` are keyword parameters in a dictionary format. For example, `fun(**data)` could be `func(name = 'Malik', age = 16)`. – Malik Brahimi May 12 '15 at 12:30
Do you understand now? – Malik Brahimi May 12 '15 at 12:33
This link is also very helpful. http://agiliq.com/blog/2012/06/understanding-args-and-kwargs/ – Nishant Upadhyay May 12 '15 at 12:36

Difference between python's parameters '*', '*args', '**', '**kwargs'

0 Answers0

Difference between python's parameters '', 'args', '', 'kwargs'