How to Get Distinct Values From Json Data without sorting

Question

I have this type of JSON data

enter image description here

I have written the code to eliminate duplicate records in JQuery

function GetUniqueTablesCategory(Data) {
  var UniqueNames = $.unique(Data, function(d) {
    return d.TableName;
  });
  return UniqueNames;
}

But I am getting this error below, can anyone please help me out to eliminate this issue.

enter image description here

It throws an error because objects cannot be sorted. The `$.unique()` method is designed to be used with an array of DOMElements, see https://api.jquery.com/jQuery.unique/ — Rory McCrossan, May 13 '15 at 07:31
Is this while running your code? It seems that you do not give an array as an argument. Did you convert the JSON into an array? — Sylvia Stuurman, May 13 '15 at 07:31
Rory McCrossan , how I will achieve this without using $.unique() method, can you please share me any link. — G R, May 13 '15 at 07:34
You need to write your own logic to replicate it, via loops. — Rory McCrossan, May 13 '15 at 07:39
I am going to write my own logic . , thanks . once I done will add in post . — G R, May 13 '15 at 07:43

Hunter · Answer 1 · 2019-08-16T13:05:16.377

3

You can write a one-liner using Set from ES6

let uniqueNames = [...new Set(Data.map(d => d.TableName))]

edited Aug 16 '19 at 13:05

answered Aug 16 '19 at 12:50

Hunter

3,080
20
23

score 1 · Answer 2 · answered May 13 '15 at 07:49

You can do that with a simple loop :

function GetUniqueTablesCategory(Data) {
  var UniqueNames = [];
  Data.forEach(function(value) {
      if (UniqueNames.indexOf(value.TableName) === -1) {
          UniqueNames.push(value.TableName);
      }
  });

  return UniqueNames ;
}

huan feng · Answer 3 · 2015-05-13T08:00:20.923

1

If underscore.js is acceptable, you can write your method like this:

function GetUniqueTablesCategory(data) {
  return _.uniq(_.map(data, function(d){return d.Name}));
}

fiddle

edited May 13 '15 at 08:00

answered May 13 '15 at 07:52

huan feng

7,307
2
32
56

score 1 · Answer 4 · edited May 23 '17 at 11:54

try something like this:

$(document).ready(function() {
 var lookup = {};
 var obj = [{'TableName': 'prop1','value5': 'prop3'},{ 'TableName': 'prop1','value5': 'prop3'}, {'TableName': 'prop3','value5': 'prop3'}];
 var array=[];
 for (var ob, i = 0; ob = obj[i++];) {
    var name = ob.TableName;

    if (!(name in lookup)) {
      lookup[name] = 1;
      array.push(name);
    }
  }

 alert(JSON.stringify(array));
 
 });//submit click

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

you can find a similar thread here also.see

How to Get Distinct Values From Json Data without sorting

4 Answers4