How to get stringstream to interpret char as an int without casting

Asked May 13 '15 at 15:53

Active May 13 '15 at 15:55

Viewed 40 times

I have some code for converting an int to a string

char val = 0x79;

std::stringstream str1, str2;

str1 << std::hex << val;   
str2 << std::hex << (short) val;
std::cout << str1.str() << std::endl;
std::cout << str2.str() << std::endl;

The output is

y    
79

The second output is what I want but I don't like having to cast the char to a short. Is there a way to get the output I want without the cast?

edited May 13 '15 at 15:55

πάντα ῥεῖ

asked May 13 '15 at 15:53

Richard Johnson

`+val`, if you like to do it that way. – T.C. May 13 '15 at 15:57
This is about input. That was about output. I'm not sure the equivalent is clear enough to call them dupes. – Lightness Races in Orbit May 13 '15 at 16:08
I did find the information I wanted though. I did not know that stringstream has an overload for char so that it is interpreted as an ascii character instead of an int. – Richard Johnson May 13 '15 at 18:25

How to get stringstream to interpret char as an int without casting

0 Answers0