Running a URL in Advanced Rest Client from a java program

Question

I have a URL of an API which is working fine if run in advanced rest client of chrome directly. I want this URL to trigger from my own REST API code which should run it in advanced rest client and stores the result in variable. How can I do this?

why do you need it to run in advanced rest client? – Romski May 14 '15 at 05:42 — Romski, May 14 '15 at 05:42

bobs_007 · Accepted Answer · 2015-05-14T06:27:41.340

Use Apache HttpClient library https://hc.apache.org/ or some other third party open source libraries for easy coding. If you are using apache httpClient lib, please google for sample code. Tiny example is here.

  HttpClient client = new DefaultHttpClient();
  HttpGet request = new HttpGet('http://site/MyrestUrl');
  HttpResponse response = client.execute(request);
  BufferedReader rd = new BufferedReader (new InputStreamReader(response.getEntity().getContent()));
  String line = '';
  while ((line = rd.readLine()) != null) {
    System.out.println(line);
  }
  return (rd);

If there are any restriction to use third party jars, you can do in plain java too.

  HttpURLConnection conn = null;
   try {

    URL url = new URL("http://site/MyRestURL");
    HttpURLConnection conn = (HttpURLConnection) url.openConnection();
    conn.setRequestMethod("GET");
    conn.setRequestProperty("Accept", ""); // add your content mime type

    if (conn.getResponseCode() != 200) {
        throw new RuntimeException("Failed : HTTP error code : "
                + conn.getResponseCode());
    }

    BufferedReader br = new BufferedReader(new InputStreamReader(
        (conn.getInputStream())));

    String output;
    while ((output = br.readLine()) != null) {
        System.out.println(output);
    }

    conn.disconnect();

  } catch (Exception e) {

    e.printStackTrace();

  }

thanks for the answer. it helped me with the url with http. but it did not work with https. i tried to look for similer structure for https, but could not find any. can you please help me with some link or such structure which takes the https url. thanks. — Shashank shekhar Dubey, May 19 '15 at 07:02
Please review question and answers. It helps you, if you want certificate solution. http://stackoverflow.com/questions/1757295/using-https-with-rest-in-java — bobs_007, May 20 '15 at 00:20
This is well explained blog. http://javaskeleton.blogspot.de/2010/07/avoiding-peer-not-authenticated-with.html — bobs_007, May 20 '15 at 00:27

score 0 · Answer 2 · answered May 20 '15 at 00:33

In plain java, try like this. My advice please try to use good open source rest/http clients. There are many example in net.

  String httpsUrl = "https://www.google.com/";
  URL url;
  try {
     url = new URL(httpsUrl);
     HttpsURLConnection con = HttpsURLConnection)url.openConnection();
    } catch (MalformedURLException e) {
     e.printStackTrace();
  } catch (IOException e) {
     e.printStackTrace();
  }

Running a URL in Advanced Rest Client from a java program

2 Answers2