Python permutations of a number

Question

My code:

a = [1,2,3]
import itertools
set(itertools.permutations(a))

I get the output as:

{(1, 3, 2), (3, 2, 1), (1, 2, 3), (2, 3, 1), (3, 1, 2), (2, 1, 3)}

Can somebody tell me how to print the numbers like:

There is not much 'so on' — three items make 6 permutations, so when you printed five of them there is only one to be added. — CiaPan, May 15 '15 at 17:23
Does this answer your question? [Python get all permutations of numbers](https://stackoverflow.com/questions/2052951/python-get-all-permutations-of-numbers) — Joe, Apr 11 '20 at 15:15

geckon · Answer 1 · 2015-05-15T17:33:09.000

4

Based on your code:

import itertools

a=[1,2,3]
permutations = set(itertools.permutations(a))

for perm in permutations:
    print("%s%s%s" % perm)

However you don't need to use set at all, so the solution (actually a better one) can be like this too:

import itertools

a=[1,2,3]
for perm in itertools.permutations(a):
    print("%s%s%s" % perm)

edited May 15 '15 at 17:33

answered May 15 '15 at 17:21

geckon

@kunal51, did you really use my solution as I posted it? You need to assign the set into the `permutations` if you want to do the first idea. Or use the second example I posted. It's better anyway. – geckon May 15 '15 at 17:27
@kunal51 it works for me, are you really trying exactly what I posted? – geckon May 15 '15 at 17:29
@kunal51, does it work now? Why are you deleting your comments? – geckon May 15 '15 at 17:37

score 1 · Answer 2 · answered May 15 '15 at 17:22

1

Cast the subelements to strings and then join them:

for perm in permutations:
    print ''.join(map(str, perm))

answered May 15 '15 at 17:22

Malik Brahimi

2 Answers2