PHP Error when check if URL Query = equals to

Question

I get an error when I try to check if a query taken from the url equals something.

Error: syntax error, unexpected T_IS_EQUAL, expecting ',' or ')'

if (isset($_GET['lang'] == 'eng')) {
    echo 'ENG';
}else if (isset($_GET['lang'] == 'alb')) {
    echo 'ALB';
}else {
    echo 'MKD';
}

Am I doing something wrong?

Thanks

RNK · Accepted Answer · 2015-05-15T19:42:26.853

3

You can not use == and isset to gether:

if (isset($_GET['lang']) && $_GET['lang']=='eng') {
    echo 'ENG';
}
else if (isset($_GET['lang']) && $_GET['lang'] == 'alb') {
    echo 'ALB';
}else {
    echo 'MKD';
}

edited May 15 '15 at 19:42

answered May 15 '15 at 19:34

RNK

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Additionally, PHP uses "elseif" not "else if" – Bryan Zwicker May 15 '15 at 19:37
I am getting an error, **syntax error, unexpected ')'**, in the first line. What is causing that? – Nikk May 15 '15 at 19:39
@Boris: Try to use above code. Let us know if there is any problem with that. – RNK May 15 '15 at 19:40
@Ronak Ah, you can. I was thinking of the limitation if you don't use curly braces. My bad :) Boris, The syntax error is because the isset should be closed before the && and there is an extra ) at the end of the if – Bryan Zwicker May 15 '15 at 19:41
@RonakPatel I copied and pasted the code above. Thats the error I get... – Nikk May 15 '15 at 19:41
@Boris: Oh. sorry.. There was 1 extra closing bracket.. Now try it – RNK May 15 '15 at 19:42

PHP Error when check if URL Query = equals to

1 Answers1