Fill array with random numbers but with limits

Question

I am trying to add random values to an array. The user has to say how many values (length) and give the minval and maxval (e.x. minval = 3 means no values under 3). This is what I've got:

int[] GetallenArray;

public IntegerArray(int length, int maxval, int minval) {

    this.GetallenArray = new int[length];
    for (int i = 0; i < GetallenArray.length; i++)
    {
        this.GetallenArray[i] = // Random values between the maxval and minval
    }
}

This question has already been answered on http://stackoverflow.com/a/3321685/832748. — Paulo Miguel Almeida, May 16 '15 at 17:05
Are you asking us to finish your code for us, or is there an issue with your code? — Ungeheuer, May 16 '15 at 17:08
also, java convention states that objects like your array should generally start with a lower case letter, then the first 'a' would be capitalized like so `int[] getAllenArray;` It simply improves readability by adhering to a standardized model of writing your code. Works wonders when someone else reads your code. — Ungeheuer, May 16 '15 at 17:11

MChaker · Answer 1 · 2015-05-16T17:10:13.620

2

Instantiate a Random object outside for loop

Random random = new Random();

Then inside for loop

this.GetallenArray[i] = random.nextInt((maxval - minval)+1) + minval;

edited May 16 '15 at 17:10

answered May 16 '15 at 17:04

MChaker

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score 1 · Answer 2 · answered May 16 '15 at 17:04

1

Random random = new Random();
this.GetallenArray = new int[length];
  for (int i = 0; i < GetallenArray.length; i++){
    this.GetallenArray[i] = random.nextInt(50) + 1; 
   //50 is the maximum and the 1 is our minimum 
  }
}

answered May 16 '15 at 17:04

Danyal Sandeelo

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Fill array with random numbers but with limits

2 Answers2