Get folder name

Question

I have some string, which is some path C:\A\B\C\D\ How can I get the folder name, say "A" or "B" or other needed. I have solution only for "D":

@echo off
setlocal enabledelayedexpansion
FOR /f %%i IN ("C:\A\B\C\D\") DO (
set parent=%%~dpi
for /F "tokens=*" %%f in ("!parent:~0,-1!") do echo %%~nf
)

Answer 1

Next code snippet splits a string to substrings delimited with the \ backslash character. Works with or without a trailing backslash, with or without blank space(s) in a string (path). Note proper quoting in set commands:

@ECHO OFF
SETLOCAL enableextensions

set "fullpath=C:\Aa\B b\Cc\D d\"
set "to_parse="%fullpath:\=" "%""

for %%G in (%to_parse%) do (
  echo %%~G       %%G
) 

Output:

==>30285354.bat
C:       "C:"
Aa       "Aa"
B b       "B b"
Cc       "Cc"
D d       "D d"
       ""

==>

Resources (required reading):

• (command reference) An A-Z Index of the Windows CMD command line
• (additional particularities) Windows CMD Shell Command Line Syntax
• (%~G etc. special page) Command Line arguments (Parameters)

Answer 2

Your question is not clear ("other folder needed" is not a specification) so I assumed you want to separate all folders into array elements, so any desired folder can be get via its index.

@echo off
setlocal EnableDelayedExpansion

set "string=C:\A\B\C\D\"

rem Separate all folders in the string into "folder" array
set i=-1
for %%a in ("%string:\=" "%") do (
   if %%a neq "" (
      set /A i+=1
      set "folder[!i!]=%%~a"
   )
)

rem Show some folders
echo The first folder:  %folder[1]%
echo The second folder: %folder[2]%
echo The last folder:   !folder[%i%]!

For further details on arrays in Batch files, see this post.