Both of the functions below perform the same set of fundamental operations get the binary repr of an integer, strip the first 2 characters, pad with zeroes then perform a slice from the right.
However, loop1 takes twice as long to run as loop2. Any insights into why that might be the case would be greatly appreciated.
def loop1(wires):
pad = '0'*wires
def _trim(m, sl):
return m[sl:]
def _pad(m):
return pad+m
for n in xrange(2**wires - 1):
m = bin(n)
m = _trim(m, 2)
m = _pad(m)
m = _trim(m, -4)
def loop2(wires):
pad = '0'*wires
for n in xrange(2**wires - 1):
m = bin(n)
m = (pad+m[2:])[-4:]
cProfile.run('loop1(24)')
cProfile.run('loop2(24)')
67108863 function calls in 22.005 seconds
Ordered by: standard name
ncalls tottime percall cumtime percall filename:lineno(function)
1 11.669 11.669 22.005 22.005 <module1>:78(loop1)
33554430 3.834 0.000 3.834 0.000 <module1>:82(_trim)
16777215 1.992 0.000 1.992 0.000 <module1>:84(_pad)
1 0.000 0.000 22.005 22.005 <string>:1(<module>)
16777215 4.510 0.000 4.510 0.000 {bin}
1 0.000 0.000 0.000 0.000 {method 'disable' of '_lsprof.Profiler' objects}
16777218 function calls in 9.482 seconds
Ordered by: standard name
ncalls tottime percall cumtime percall filename:lineno(function)
1 5.160 5.160 9.482 9.482 <module1>:96(loop2)
1 0.000 0.000 9.482 9.482 <string>:1(<module>)
16777215 4.322 0.000 4.322 0.000 {bin}
1 0.000 0.000 0.000 0.000 {method 'disable' of '_lsprof.Profiler' objects}