aggregate by two columns R

Question

I have a dataset with three column

  Date1      StudentId  Status
  08/04/2014 155261     Yes
  08/04/2014 155261     No
  08/25/2014 236991     Yes
  08/27/2014 236991     Yes
  08/29/2014 236991     Yes

I am trying to aggregate the Status by Id and Date1, such that the final dataset will be like this

  Date1      StudentId  Response
  08/04/2014 155261     Yes, No
  08/25/2014 236991     Yes
  08/27/2014 236991     Yes
  08/29/2014 236991     Yes

I tried using the gsub function but it didnt work, it only aggregates based on StudentId and skips the Date, any help on this issue is much appreciated.

 dataset1[,Response:=gsub("(, )+$","",c(paste(Status,collapse=", "),rep("",.N-1))),by=c("StudentId ","Date1")]

Are you using a `data.table` (required for use of `:=`)? What does it mean that it didn't work here? — Frank, May 21 '15 at 20:16
@Frank, it was only aggregating based on StudentId and unable to combine both StudentId and Date, bgoldst solution fixed the problem — Ezra Polson, May 21 '15 at 20:30
@Ezra if you already have a `data.table` object, using base R aggregating operations is like riding a bike when you own a Jaguar (unless you are doing it for the sports) — David Arenburg, May 21 '15 at 20:39

bgoldst · Accepted Answer · 2015-05-21T20:39:46.323

3

df <- data.frame(Date1=c('08/04/2014','08/04/2014','08/25/2014','08/27/2014','08/29/2014'), StudentId=c(155261,155261,236991,236991,236991), Status=c('Yes','No','Yes','Yes','Yes') );
aggregate(Status~Date1+StudentId,df,paste,collapse=', ');
##        Date1 StudentId  Status
## 1 08/04/2014    155261 Yes, No
## 2 08/25/2014    236991     Yes
## 3 08/27/2014    236991     Yes
## 4 08/29/2014    236991     Yes

You can rename the column from Status to Response separately:

names(df)[names(df)=='Status'] <- 'Response';

edited May 21 '15 at 20:39

answered May 21 '15 at 20:20

bgoldst

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Just be aware that `Status` is a list and I doubt it useful for the OP in any way, see `str(aggregate(Status~.,df,paste))`. So this solution is basically wrong. An optional solution is `aggregate(Status~.,df,toString)` – David Arenburg May 21 '15 at 20:32
1

Ah, I see now, effectively `paste` in the first version is the same as `as.character`. As long as the "edit" version is what you'd recommend, you might as well put it at the top, right? – Frank May 21 '15 at 20:38
Why not just `aggregate(Status~.,df,toString)` though? – David Arenburg May 21 '15 at 20:38
2

Maybe because that function is too obscure for us to know :) – Frank May 21 '15 at 20:39
1

@Frank don't even start, mister `[.listof` – David Arenburg May 21 '15 at 20:40

Frank · Answer 2 · 2015-05-21T20:46:37.200

No gsub is needed to concatenate strings (thanks to @DavidArenburg for a simplifcation):

DT1 <- DT[,list(Response=toString(Status)),by=list(Date1,StudentId)]

If students might show up multiple times with the same status, you'll want to use unique on Status.

Instead of using a string, you could store the values in a list with list(String).

The good: Set operations like %in% can be used and may be more intuitive than string parsing.
The bad: List columns cannot be used in by operations and are generally cumbersome.

aggregate by two columns R

2 Answers2