Comparison between two longs doesn't work as expected

Question

this will be a simple question (or at least i think). I have to compare a Long object to a long primitive.

My code simplified:

long primitiveLong = 285825645621;
Long objectLong = new Long(285825645621);

if(primitiveLong == objectLong.longValue()){
    System.out.print("They are equals");
}

I expected that it would have worked, but it didn't, can someone explain me why?

Thanks in advance.

EDIT

Ok, i did a mistake using explicit numbers, i'll put here my code:

long identifier = mMarkers.get(marker);
long currentId = item.getId().longValue();

if (currentId==identifier)
    System.out.print("They are equals");

In debug

enter image description here

EDIT 2

It was an IDE (Android Studio) bug in debug mode, i tried on another IDE and it worked well with same code. So thanks to everyone for the answers, but the problem was another, that i couldn't expect.

Should the code have entered the if loop or not or should we just take a guess about what you believe should have happened :) — Chetan Kinger, May 28 '15 at 08:08
@ChetanKinger The code should have entered in the if statement — Giorgio Antonioli, May 28 '15 at 08:14
It will not compile, For compilation add L in the end of number, then this code should work as-is @ChetanKinger `if` is not a loop but a statement;) — Nitin Dandriyal, May 28 '15 at 08:15

score 0 · Answer 1 · answered May 28 '15 at 08:08

0

First this must should give you compile error because compiler think of 285825645621 as an Integer but it is larger than int, so you need to change your code like this:

long primitiveLong = 285825645621l; //add and l at the end of your number so compiler know that it is a long not an int
Long objectLong = new Long(285825645621l); //do the same thing here

if(primitiveLong == objectLong.longValue()){
    System.out.print("They are equals");
}

and this will print : They are equals

answered May 28 '15 at 08:08

Lrrr

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As i said this is a more simplified version of my code. I haven't explicit numbers, but methods that return them – Giorgio Antonioli May 28 '15 at 08:14
@Fondesa so you dont simplify your code well! please provide more information, with the data that you provided, I couldnt explain more about why that happened. – Lrrr May 28 '15 at 08:16
See the edits to my question! – Giorgio Antonioli May 28 '15 at 08:21
@Fondesa are you sure you provide correct data now? they are both `long` with same value so `==` should work! – Lrrr May 28 '15 at 08:32

Anil Reddy Yarragonda · Answer 2 · 2015-05-28T08:13:48.947

0

You can use your literal value still this limit 285825645

If you are using beyond the limit you will get compile error 

long primitiveLong = c;
            Long objectLong = new Long(285825645);

            if(primitiveLong == objectLong.longValue()){
                System.out.print("They are equals");
            }

edited May 28 '15 at 08:13

answered May 28 '15 at 08:10

Anil Reddy Yarragonda

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Comparison between two longs doesn't work as expected

2 Answers2