This code is not running is google chrome, get syntax error in function definition

Question

function validateThisField(fieldID,fieldType="text"){

//var ID=fieldID.substr(fieldID.length - 1);

//var fieldSubName = fieldID.slice(0, -1);
var fieldVal = jQuery('#'+fieldID).val();
if(fieldType=="text" && fieldVal.length > 0){
    jQuery('#'+fieldID+'_lbl').addClass('errlabel');
    jQuery('#'+fieldID).removeClass('associate_error_border_radius');
}else{
    jQuery('#'+fieldID+'_lbl').removeClass('errlabel');
    jQuery('#'+fieldID).addClass('associate_error_border_radius');

This is html

`<input class="associate_error_border_radius" onblur="validateThisField('assoc_firstname_1');" name="assoc_firstname_1" id="assoc_firstname_1" type="textbox">`

This code is running in Mozilla but in google chrome get syntax error in function definition.

It would help if you tell us what the syntax error is, instead of asking us to guess. — crafter, May 30 '15 at 13:01
This is syntax error in Google chrome: "Uncaught SyntaxError: Unexpected token =" — Umashankar Saw, Jun 01 '15 at 05:50

score 0 · Answer 1 · edited May 23 '17 at 10:26

0

You can't have default parameters in Javascript so you need to remove the '="text"' in your function definition

function validateThisField(fieldID,fieldType="text"){

to

function validateThisField(fieldID,fieldType){

See this SO post for more information Set a default parameter value for a JavaScript function

edited May 23 '17 at 10:26

Community

1
1

answered Jun 01 '15 at 13:22

Scott Anderson

1,363
1
10
19

Norkos · Accepted Answer · 2015-06-01T14:05:57.480

0

If you want to use default parameters in javascript use something like this:

function foo(param){
    //'default' is the default value
    if(typeof param === 'undefined'){ param = 'default'; }
}

edited Jun 01 '15 at 14:05

answered Jun 01 '15 at 13:57

Norkos

171
1
13

This code is not running is google chrome, get syntax error in function definition

2 Answers2