list to dictionary python

Question

This is my list

myList = ['Bob', '5-10', 170, 'Tom', '5-5', 145, 'Bill', '6-5', '215']

I want to make into a dictionary like this.

{'Bob': ['5-10', 170], 'Bill': ['6-5', '215'], 'Tom': ['5-5', 145]}

I came up with this but it is very ugly and doesn't scale up.

def MakeDict():
    d = {}
    for x, i  in zip(myList, range(len(myList))):
       if i in (0, 3, 6):
           name = x
       elif i in (1, 4, 7):
           hieght = x
       elif i in (2, 5, 8):
           wieght = x
          d[name] = [hieght, wieght]
return d

What can I do?

For starters, you could indent your sample code, it would make it more readable. — Srini, May 30 '15 at 01:37
FYI, you can replace the `zip(...)` call with `enumerate(myList)`. — John Kugelman, May 30 '15 at 01:39

score 5 · Accepted Answer · edited May 23 '17 at 11:43

Convert your list to an iterator
Now loop over it to get the keys.
For values during each iteration call itertools.islice on the iterator. Then call list() on the slice object to get a list.

>>> from itertools import islice
>>> myList = ['Bob', '5-10', 170, 'Tom', '5-5', 145, 'Bill', '6-5', '215']
>>> it = iter(myList)
>>> {key: list(islice(it, 2)) for key in it}
{'Bob': ['5-10', 170], 'Bill': ['6-5', '215'], 'Tom': ['5-5', 145]}

If you don't want to import anything use zip(*[iterator]*n) magic:

>>> {key: [height, weight]  for key, height, weight in zip(*[iter(myList)]*3)}
{'Bob': ['5-10', 170], 'Bill': ['6-5', '215'], 'Tom': ['5-5', 145]}

score 0 · Answer 2 · answered May 30 '15 at 01:48

0

I would use itertools.

Here is pushing you in the right direction:

from itertools import islice

See the examples at itertools.islice

answered May 30 '15 at 01:48

waldens

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1
5

1

It actually answers the question (or at least makes a good attempt at it). – Vlad Schnakovszki May 30 '15 at 09:51

list to dictionary python

2 Answers2