INTtoCHAR function couts wrong value

Question

here is what my function looks like:

signed char INTtoCHAR(int INT)
{
    signed char CHAR = (signed char)INT;
    return CHAR;
}

int CHARtoINT(signed char CHAR)
{
    int INT = (int)CHAR;
    return INT;
}

It works properly that it assigns the int value to the char, but when I want to cout that char then it gives me some weired signs. It compiles without errors.

My testing code is:

int main()
{
  int x = 5;
  signed char after;
  char compare = '5';
  after = INTtoCHAR(5);

  if(after == 5)
  {
      std::cout << "after:" << after << "/ compare: " << compare << std::endl;
  }


  return 0;
}

After is indeed 5 but it doesn't print 5. Any ideas?

It is garbage output @Mikael. However, with my answer, you will get the number. — gsamaras, May 30 '15 at 12:50
@Somebody, can you please confirm that my answer is correct? :) — gsamaras, May 30 '15 at 13:07
@Somebody, you asked for ideas, you got 2, would you care to say something about them? :) — gsamaras, May 31 '15 at 12:29

score 2 · Answer 1 · edited May 30 '15 at 15:34

2

Adding to the above answer using the unary operator +, there is another way as well: typecasting.

std::cout << "after:" << (int)after << "/ compare: " << compare << std::endl;

Correct output

edited May 30 '15 at 15:34

gsamaras

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answered May 30 '15 at 13:24

Ayushi Jha

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How didn't I think of that? Nice answer karma_geek! +1 – gsamaras May 30 '15 at 15:03
1

@gsamaras: I had +1'ed your answer too, because I didn't know about the unary operator method. Thanks to you too :) – Ayushi Jha May 30 '15 at 15:29
1

Thanks geek, nice top answer too! ;) – gsamaras May 30 '15 at 15:34

score 1 · Answer 2 · edited May 23 '17 at 11:43

1

Use +after while printing, instead of after. This will promote after to a type printable as a number, regardless of type.

So change this:

std::cout << "after:" << after << ", compare: " << compare << std::endl;

to this:

std::cout << "after:" << +after << ", compare: " << compare << std::endl;

For more, see this answer.

edited May 23 '17 at 11:43

Community

1
1

answered May 30 '15 at 12:47

gsamaras

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INTtoCHAR function couts wrong value

2 Answers2