How to turn Binary String into text?

Question

I am working on a personal project. I want to create an encryption program that lets you encrypt, and decrypt a String using a key. Almost finished only need help with the final part. I want to convert a binary String into a text. Let's say the binary outcome(which I want to convert into a normal text) is:

01001000011000010110100001100001

This converted into text is "Haha".

NOTE: I am only working with BigIntegers since Almost every number I am using is too big for a normal Integer.

EDIT: Found the answer using this this code:

    StringBuffer output = new StringBuffer();
for (int i = 0;i < input.length();i += 8) {
  output.append((char) Integer.parseInt(input.substring(i, i + 8), 2));
}
       System.out.println(output);

possible duplicate http://stackoverflow.com/questions/4211705/binary-to-text-in-java — AshBringer, May 31 '15 at 14:21
@BipBip Doesn't help since I am working with BigIntegers. And they are working with ints. — fihdi, May 31 '15 at 14:23
@fihdi You can take reference from this question http://stackoverflow.com/questions/5716830/convert-biginteger-to-shorter-string-in-java/5717191#5717191 — iYoung, May 31 '15 at 14:49
@RajatDeepSingh This seems to work, can you also do this with Base36? Because I am using base 36 right now. — fihdi, May 31 '15 at 15:12
Please post your solution as an answer and accept it so it can help others — John La Rooy, Oct 26 '15 at 09:42

score 0 · Answer 1 · answered Nov 28 '15 at 07:22

This code will do it in one line:

String str = "01001000011000010110100001100001";

String decoded = Arrays.stream(str.split("(?<=\\G.{8})"))
    .map(s -> Integer.parseInt(s, 2))
    .map(i -> "" + Character.valueOf((char)i.intValue()))
    .collect(Collectors.joining("")); // "Haha"

It can probably be made prettier, but I didn't have an IDE handy (just thumbed it in on my phone).

You'll note that BigInteger isn't needed, and this code handles input of arbitrarily large length.

How to turn Binary String into text?

1 Answers1