If you need to do that, then using the database and store the uploaded items in its coloumn is the better way..
But to answer your question
You can do something like this.
Step 1 :
Read all the files in your directory
$dir = 'up/';
$files = scandir($dir);
Step 2 :
Do a foreach and print it in your file (If you need to display an image it can be possible and you can have links over there )
$i = 1;
foreach ($files as $key)
{
echo $i.' - '.$key.'<hr>';
echo "<a href='up/".$key."'><img src ='up/".$key."'>".$key."</a>";
$i++;
}
So you can have something like this..
<?php
$dir = 'up/';
$files = scandir($dir);
echo '<h1>List of Uploaded Files</h1> <br><hr>';
$i = 1;
foreach ($files as $key)
{
echo $i.' - '.$key.'<hr>';
echo "<a href='up/".$key."'><img src ='up/".$key."'>".$key."</a>";
$i++;
}
echo 'End of Files';
?>
Note :
I am using the directory name as up you can have it any name of your own.
If you have this file as list.php then it should have a sub folder named as up and you should have files inside it.. You can have image or text file as you need.
Update :
If you just want to list the files, then you just need to echo it
<?php
$dir = 'up/';
$files = scandir($dir);
echo '<h1>List of Uploaded Files</h1> <br><hr>';
$i = 1;
foreach ($files as $key)
{
echo $i.' - '.$key.'<hr>';
$i++;
}
echo 'End of Files';
?>
Here's the eval link
Update 2 :
As the OP needs to have an anchor tag and wants to remove the directory level Here's the updated code
<?php
$dir = 'up/';
$files = scandir($dir);
echo '<h1>List of Uploaded Files</h1> <br><hr>';
$i = 1;
foreach ($files as $key)
{
if ($i>3)
{
$j = $i-3;
echo $j."<a href='up/".$key."'>".$key."</a><hr>";
}
$i++;
}
echo 'End of Files';
?>
Here's the Eval
