I`ve tried to implement dot product of this two arrays using AVX https://stackoverflow.com/a/10459028. But my code is very slow.
A
and xb
are arrays of doubles, n is even number. Can you help me?
const int mask = 0x31;
int sum =0;
for (int i = 0; i < n; i++)
{
int ind = i;
if (i + 8 > n) // padding
{
sum += A[ind] * xb[i].x;
i++;
ind = n * j + i;
sum += A[ind] * xb[i].x;
continue;
}
__declspec(align(32)) double ar[4] = { xb[i].x, xb[i + 1].x, xb[i + 2].x, xb[i + 3].x };
__m256d x = _mm256_loadu_pd(&A[ind]);
__m256d y = _mm256_load_pd(ar);
i+=4; ind = n * j + i;
__declspec(align(32)) double arr[4] = { xb[i].x, xb[i + 1].x, xb[i + 2].x, xb[i + 3].x };
__m256d z = _mm256_loadu_pd(&A[ind]);
__m256d w = _mm256_load_pd(arr);
__m256d xy = _mm256_mul_pd(x, y);
__m256d zw = _mm256_mul_pd(z, w);
__m256d temp = _mm256_hadd_pd(xy, zw);
__m128d hi128 = _mm256_extractf128_pd(temp, 1);
__m128d low128 = _mm256_extractf128_pd(temp, 0);
//__m128d dotproduct = _mm_add_pd((__m128d)temp, hi128);
__m128d dotproduct = _mm_add_pd(low128, hi128);
sum += dotproduct.m128d_f64[0]+dotproduct.m128d_f64[1];
i += 3;
}