maven surefire: how to print current test being run?

Question

Is there any way to get maven surefire to print the name of every unit test (i.e., test method) it's starting?

Something like:

testFoo: ... passed
testBar: ... failed

Possibly duplicate of http://stackoverflow.com/questions/15203756/maven-displaying-unit-test-currently-running — Paul Verest, Nov 10 '16 at 06:06

score 6 · Answer 1 · answered Nov 10 '16 at 10:35

In details

package com.example.mavenproject;

import org.junit.runner.Description;
import org.junit.runner.Result;
import org.junit.runner.notification.RunListener;

/**
 * @author Paul Verest
 */
public class PrintOutCurrentTestRunListener extends RunListener {
    @Override
    public void testRunStarted(Description description) throws Exception {
        // TODO all methods return null
        System.out.println("testRunStarted " + description.getClassName() + " " + description.getDisplayName() + " "
                + description.toString());
    }

    public void testStarted(Description description) throws Exception {
        System.out.println("testStarted "
                + description.toString());
    }

    public void testFinished(Description description) throws Exception {
        System.out.println("testFinished "
                + description.toString());
    }

    public void testRunFinished(Result result) throws Exception {
        System.out.println("testRunFinished " + result.toString()
                + " time:"+result.getRunTime()
                +" R"+result.getRunCount()
                +" F"+result.getFailureCount()
                +" I"+result.getIgnoreCount()
                );
    }
}

and in pom.xml

<dependencies>
    <dependency>
        <groupId>junit</groupId>
        <artifactId>junit</artifactId>
        <version>4.12</version>
        <scope>test</scope>
    </dependency>
</dependencies>
<!-- -->
<build>
    <plugins>
        <plugin>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-surefire-plugin</artifactId>
            <version>2.19.1</version>
            <configuration>
                <properties>
                    <property>
                        <name>listener</name>
                        <value>com.example.mavenproject.PrintOutCurrentTestRunListener</value>
                    </property>
                </properties>
            </configuration>
        </plugin>
    </plugins>
</build>

Does not appear as though `System.out.println` makes it into the Maven console log, nor any report. — ThaDon, Nov 06 '17 at 15:17

score 4 · Accepted Answer · answered Jun 01 '15 at 20:05

4

It's a bit of stretch, but you could implement a RunListener and add it to surefire. See how to configure it here.

answered Jun 01 '15 at 20:05

Robert

452
2
12

Instead, why not log the test name from the test code itself ? – MasterJoe Jul 01 '20 at 20:40
For anyone using JUnit 5, you can now provide a TestExecutionListener : https://junit.org/junit5/docs/current/user-guide/#running-tests-listeners – Adrien H Sep 27 '22 at 12:07

score 0 · Answer 3 · answered Sep 21 '20 at 05:37

0

Alternatively you can run maven in debug mode with --debug or -X flags

answered Sep 21 '20 at 05:37

David stands with Ukraine

2,267
2
18
23

It doesn't log successfully executed tests. – ka3ak Aug 12 '21 at 07:17

maven surefire: how to print current test being run?

3 Answers3