Using a form value in php if/else

Asked Jun 01 '15 at 21:59

Active Jun 01 '15 at 21:59

Viewed 18 times

The form code :

<form method="post">
                <input type="text" name="q" /> 
                <input type="submit" name="search" value="Find Workorder" class="btn btn-success"/>
                </form>

example php code :

include 'database.php';
$pdo = Database::connect();   
$sql = 'SELECT whatever FROM wherever ORDER BY id DESC';
$rows = $pdo->query($sql);
foreach ($pdo->query($sql) as $row) 
{
echo
whatever
}

if ($q)
{
$sql2 = 'SELECT whatever FROM wherever WHERE whatever LIKE '%$q%' ORDER BY id DESC';
$rows = $pdo->query($sql);
foreach ($pdo->query($sql) as $row) 
{
echo
whatever
}

I keep on getting an undefined variable error, when the variable "q" is obviously being defined whenever a _POST is made, does anyone know why this is?

asked Jun 01 '15 at 21:59

Steven

`if ($q)` where is `$q` defined? – spiderman Jun 01 '15 at 22:01
You must have learned php on a stoneage/braindead system where register_globals was still enabled. $q is **VERY** undefined in your code. – Marc B Jun 01 '15 at 22:01
I named the form as "q", whenever you post, does that not convert as $q? – Steven Jun 01 '15 at 22:02
1

No, use `if (isset($_POST['q'])) { ... }` instead. That's where q is put. – Joel Hinz Jun 01 '15 at 22:02
ohhh no thats HTML.. ` ` how does that define a `php` variable? – spiderman Jun 01 '15 at 22:03
ah, thank you very much @JoelHinz – Steven Jun 01 '15 at 22:03
@JoelHinz, good catch what he meant!, post as answer and let him close it – spiderman Jun 01 '15 at 22:04
@spiderman I would have, but it's been closed. :) No biggie, though. – Joel Hinz Jun 01 '15 at 22:05

Using a form value in php if/else

0 Answers0