java code: if statement not the expected output

Question

The output should be the salary + rise 4% or 6%. This is my code:

int x = input.nextInt();    //x 1,2 or3//
System.out.println("enter the sallary:");
int y = input.nextInt();    // salary//
if (x == 1) {
    double z = 6/100*y + y;
    System.out.print("excellent ur sallary is :");
    System.out.print(z);
} else {
    double z = 4/100*y + y;
    System.out.print("good ur sallary is :");
    System.out.print(z);
 }

But the output is always only the value of y (the salary without the rising) !

Also how I can print that sentence and the variable z in the same line? Like this for example:

System.out.print("good ur sallary is :", z);

but that doesn't work.

BTW the downvotes are a bit brutal. It's not an obvious error to someone that is relatively new to programming. — Eric J., Jun 03 '15 at 22:47

Nayuki · Accepted Answer · 2015-06-03T22:50:14.967

0

First part: When you write 6/100*y, it's equal to (6/100)*y. But the expression 6/100 is integer division, which is equal to 0. Thus 0*y = 0. What you want to do is change 6/100 to 0.06, and 4/100 to 0.04.

Second part: The correct syntax is System.out.println("YOUr salary is: " + z);.

edited Jun 03 '15 at 22:50

answered Jun 03 '15 at 22:49

Nayuki

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Without explaining why those changes should be made, this is a comment and not a (good) answer. – Eric J. Jun 03 '15 at 22:50

java code: if statement not the expected output

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