New line not working

Question

Description:

I have the follwoing code:

        if(isset($riskTriggerFlag) && $riskTriggerFlag==1) // if risk_mitigator process reads and offer weight is  maintained based on offer mentioned.
        {
            echo "Risk Weight: ".$risk_weight ."\n";
            $randNo = rand(1,100);

            echo "Random Weight: ". $randNo ."\n";
            if($randNo < intval(100 - $risk_weight))
            {
                $flagThrowPostback = 1;
            }
        }

As you can see,I am putting \n in the text,but still the message in getting printed in this matter:

Risk Weight: 20 Random Weight: 20

What am I doing wrong?

Note:

I can't use br tag or nl2br() since the total page is just a php page, and I don't want to add any html tags.

output on broswer is coming like this:

<html>
<head></head>
<body>Multiple row Risk Weight: 20 Random Weight: 20 </body>
</html>

Do you look at the output in the browser? (Probably you do, so you have to use br tags otherwise your web browser won't show you a new line) — Rizier123, Jun 04 '15 at 10:04
[`PHP_EOL`](http://stackoverflow.com/questions/21373478/n-vs-php-eol-vs-br) should work fine. — Andrei, Jun 04 '15 at 10:04
So as you look at the output in the browser you have to use `br` tags. Or you put your output into `pre` tags, then you can use your `\n` — Rizier123, Jun 04 '15 at 10:06
@Rizier123, I used `\n` already in my code,but still its coming in a single line. ( — Saswat, Jun 04 '15 at 10:07
I think better way is to check whether php file is executed from CLI or browser. In case it is from browser then use
else newline. — Elixir Techne, Jun 04 '15 at 10:08
I'm voting to close this as whatever the real issue is the OP apparently doesn't want to explain it correctly... — Laurent S., Jun 04 '15 at 10:15
@Bartdude, all the people who commented got the clear idea of what I wanted, yet you think that's its not explained enough.... that's strange — Saswat, Jun 04 '15 at 10:16
@Bartdude, I am reading this page currently on browser,but later it wil be run via commandline method.. That's why I wanted it with free of tags.... for current scenario, to complete my testing with message, I compromised with the little help I am getting — Saswat, Jun 04 '15 at 10:28
We can't guess this out of your original question... My suggestion now you explained this, and if you don't want any extra tag (even `
`), would be to go for a javascript solution based on [this one](http://stackoverflow.com/questions/784539/how-do-i-replace-all-line-breaks-in-a-string-with-br-tags), targetting only text contained in specific parent, which can be filtered based on css class for example. You could also go for a "test mode" in PHP with a flag activated by some querystring parameter for example, which would be conditionnally adding some `nl2br()`calls when ran in test mode — Laurent S., Jun 04 '15 at 11:55

Elixir Techne · Answer 1 · 2015-06-05T04:08:29.273

I think better way is to check whether php file is executed from CLI or browser. In case it is from browser then use
else newline.

$newline = "<br />";
if (PHP_SAPI === 'cli')
{
   // ...
   $newline = "\n";
} 
if(isset($riskTriggerFlag) && $riskTriggerFlag==1) // if risk_mitigator process reads and offer weight is  maintained based on offer mentioned.
    {
        echo "Risk Weight: ".$risk_weight . $newline;
        $randNo = rand(1,100);

        echo "Random Weight: ". $randNo . $newline;
        if($randNo < intval(100 - $risk_weight))
        {
            $flagThrowPostback = 1;
        }
    }

New line not working

Description:

Note:

1 Answers1