PHP whitescreen of death on perfectly good code

Asked Jun 05 '15 at 16:33

Active Jun 05 '15 at 16:33

Viewed 23 times

So far I've only been messing around with javascript so, I have no idea how php works. I assume I've made some newbie mistake somewhere above which I can't fine.

Thank for the help!

<?php
require('youtube-dl.class.php');
if(!isset($_POST['submit'])) {
    $url = $_POST['url'];
    try {
        new yt_downloader($url, TRUE, 'audio');
    }
    catch (Exception $e) {
        die($e->getMessage());
    }
}
?>

The downloader incase that's important: https://github.com/eyecatchup/php-yt_downloader/

asked Jun 05 '15 at 16:33

OvenMann

1

Turn on error reporting – John Conde Jun 05 '15 at 16:33
2

[Use this for white screen of death...](http://php.net/manual/en/function.error-reporting.php) – Funk Forty Niner Jun 05 '15 at 16:33
*"So far I've only been messing around with javascript so"* - What JS? – Funk Forty Niner Jun 05 '15 at 16:35
1

So if `submit` is NOT set, run the codez? – AbraCadaver Jun 05 '15 at 16:36
@AbraCadaver yeah, they like it when code runs not. *Yoda talk*. – Funk Forty Niner Jun 05 '15 at 16:37
If the field 'submit' is posted the page will return nothing. – Barry Jun 05 '15 at 16:37
1

`if(isset($_POST['submit'])) {...}` perhaps? and make sure it's "named" and that the form does imply a POST method. – Funk Forty Niner Jun 05 '15 at 16:38

PHP whitescreen of death on perfectly good code

0 Answers0