Accessing a character pointer

Question

#include<stdio.h>

char* output;
int main() {
output="Hello";
output[0]='r'; // This line shows error . Please assist as to why 
printf(output);
return 0;
}

Please tell the correct way to do so . I know this might be a stupid question for most of the people , but I wanted to perform an operation like this (the line with comment ) ,so this is just a short example of the problem that i am facing.

Thank You

String literals are immutable. Use `char output[6];` and `strcpy` instead — Spikatrix, Jun 07 '15 at 06:01

score 0 · Answer 1 · answered Jun 07 '15 at 06:04

0

When you write:

output = "Hello";

Then char pointer output points to a string. By their very nature strings are immutable objects.

answered Jun 07 '15 at 06:04

bhavesh

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**string** should be **string literal**. – Yu Hao Jun 07 '15 at 06:09
Thanks , problem solved – Sagar Singh Jun 07 '15 at 06:37

Accessing a character pointer

1 Answers1