How to make this json using java

Question

I want to create this json using java ,somebody help

{
 "comment": "Check out developer.linkedin.com!",
 "content": {
   "title": "LinkedIn Developers Resources",
   "description": "Leverage LinkedIn's APIs to maximize engagement",
   "submitted-url": "https://developer.linkedin.com",  
"submitted-image-url": "https://example.com/logo.png"
 },
 "visibility": {
  "code": "anyone"
}  
}

Can you elaborate more on this? Also, show us what you have tried so far. One liner answer to this question would be - create your Java objects as per the JSON structure and use JSON-Java (and vice versa) conversion library (eg. GSON). — Pramod Karandikar, Jun 08 '15 at 11:15
I'd suggest a googling on how to use FasterXML's Jackson datamapper — Robin Jonsson, Jun 08 '15 at 11:16

score 0 · Answer 1 · answered Jun 08 '15 at 11:40

Create java class to map to Json..something like

public class JavaClass  {
private String comment;
 // other Can be in map or java class for content
private Map<String, Object> additionalProperties = new HashMap<String, Object>();

 //getters and setters
}

populate the object and use any library to convert to Json object.
```
 JavaClass  object = new JavaClass ();
 object.set(....)
```

Now using JSONbject

 JSONObject jsonObj = new JSONObject( object );
 System.out.println( jsonObj );

score 0 · Answer 2 · answered Jun 08 '15 at 11:42

try{
        JSONObject jsonObject = new JSONObject();
        jsonObject.put("comment", "Check out developer.linkedin.com!");
        JSONObject contentJsonObject = new JSONObject();
        contentJsonObject.put("title", "LinkedIn Developers Resources");
        contentJsonObject.put("description", "Leverage LinkedIn's APIs to maximize engagement");
        contentJsonObject.put("submitted-url", "https://developer.linkedin.com");
        contentJsonObject.put("submitted-image-url", "https://example.com/logo.png!");
        jsonObject.put("content",contentJsonObject);
        JSONObject visibilityJsonObject = new JSONObject();
        visibilityJsonObject.put("code", "anyone");
        jsonObject.put("visibility",visibilityJsonObject);
    }catch(JSONException ex){
        Log.i("json ex: ",ex.toString());
    }

How to make this json using java

2 Answers2